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The power input to a 3-phase induction machine is 60 kW. The stator loses total 1 kW and neglect the air gap loss in the machine. Find the rotor copper loss per phase if the motor is running with a slip of 3%.?
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The power input to a 3-phase induction machine is 60 kW. The stator lo...
The power input to a 3-phase induction machine is 60 kW. The stator loses total 1 kW and neglect the air gap loss in the machine. Find the rotor copper loss per phase if the motor is running with a slip of 3%.

Given:
- Power input to the machine (P) = 60 kW
- Stator losses (P_stator) = 1 kW
- Slip (S) = 3%

To find:
- Rotor copper loss per phase (P_rotor)

Solution:
The input power to the induction machine is equal to the sum of the stator losses and the output power. Mathematically, it can be expressed as:

P = P_stator + P_rotor

Substituting the given values:

60 kW = 1 kW + P_rotor

P_rotor = 60 kW - 1 kW
P_rotor = 59 kW

The output power of the machine can be calculated using the formula:

P_output = P * (1 - S)
P_output = 60 kW * (1 - 0.03)
P_output = 60 kW * 0.97
P_output = 58.2 kW

The rotor copper loss per phase can be calculated by subtracting the stator losses from the output power:

P_rotor = P_output - P_stator
P_rotor = 58.2 kW - 1 kW
P_rotor = 57.2 kW

Therefore, the rotor copper loss per phase is 57.2 kW.
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The power input to a 3-phase induction machine is 60 kW. The stator loses total 1 kW and neglect the air gap loss in the machine. Find the rotor copper loss per phase if the motor is running with a slip of 3%.?
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