The image of an object formed by a mirror is real, inverted and is of ...
Given Information:
- Image formed by mirror is real, inverted and of magnification -1.
- Distance of image from mirror is 40 cm.
Finding Object Distance:
Let the distance of the object from the mirror be 'u'.
Using mirror formula, 1/v + 1/u = 1/f where f is the focal length of the mirror.
As the image is real and inverted, v is negative.
Also, magnification = -v/u = -1.
Therefore, -(-u)/u = -1, which gives u = -v = -40 cm.
So, the object is placed at a distance of 40 cm from the mirror.
Finding New Image Position:
If the object is moved 20 cm towards the mirror, its new distance from the mirror would be u' = u - 20 = -60 cm.
Using mirror formula, 1/v' + 1/u' = 1/f
As the magnification remains the same, v' = -u.
Substituting values, we get 1/(-u) + 1/(-60) = 1/f
Solving this equation, we get f = -30 cm.
Using mirror formula again, we can find the new image distance:
1/v' + 1/u' = 1/f
1/v' + 1/(-60) = 1/-30
1/v' = 1/-30 + 1/60 = 0
Therefore, v' is at infinity, which means the image is formed at the focus of the mirror.
Ray Diagram:
When the object is at a distance of 40 cm from the mirror:
- A ray of light from the object parallel to the principal axis gets reflected back and passes through the focus.
- A ray of light from the object passing through the focus gets reflected back parallel to the principal axis.
- The intersection of these two reflected rays gives the real inverted image of the object.
When the object is moved 20 cm towards the mirror:
- The new object is closer to the mirror, so the reflected rays will be more divergent.
- The new image will be at the focus of the mirror.
- The ray diagram for this situation will have the same two reflected rays, but they will appear more divergent than before.