The image of an object formed by a mirror is real inverted and is of magnification -1 if the image is at the distance of 30 cm from the mirror where is the object placed find the position of the image if the object is no more 20cm towards the mirror.what is the nature of image obtained ?

Question

Answer

Given the image formed is real inverted and its magnification is -1

If magnificaion is -1 then it means the nature of the image is real invertedand of the same size . in this case the object is placed at C and image is formed at C.

If the image is at a distance of 30cm from the mirror then the object is also at a distance of 30cm from the mirror.

If the object is moved 20cm towards the mirror then the position of the object is between the pole and the principal focus (f=15cm)

When the object is moved 20cm towards the mirror then the position of the image will be by the mirror formula, and the nature of the image is virtual erect and enlarged...!

HOPE THIS HELPS..........!!😇😇

Answer

Explanation:

Given, u = -30cm, v = -30cm, m = -1

Using mirror formula:

1/v + 1/u = 1/f

Putting values, we get:

1/v + 1/-30 = 1/f

1/v = 1/30 - 1/f

1/v = (f - 30)/30f

v = 30f/(f - 30)

Also, m = -v/u

-1 = -v/u

v = u

Using the above two equations, we get:

30f/(f - 30) = -30

f = -60cm

Answer:

The nature of the image obtained is real, inverted, and of the same size as the object. When the object is moved towards the mirror from a distance greater than the focal length, the image formed by the mirror is virtual, erect, and magnified. This is because the image formed is behind the mirror and cannot be projected on a screen. However, when the object is moved towards the mirror from a distance less than the focal length, the image formed by the mirror is virtual, erect, and magnified. This is because the image formed is in front of the mirror and can be projected on a screen. The focal length of the mirror is negative for a concave mirror and positive for a convex mirror.

Answer

M=-2
v= 30
u=?
m=v/u
m=30/u
-2=30/u
u=-15
1/v+1/u=1/f
1/30+1/-15
f= -30

Similar Class 10 Doubts

An object is placed perpendicular to the principalaxis of a convex lens of focal length 20 cm. The distance of the object from the lens is 30 cm. Find(i) the position(ii) the magnification and(iii) the nature of the image formed.

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