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A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?
- a)y = 3sin(2πx – 2πt)
- b)y = 3sin(2πt – 2πx)
- c)x = 3sin(2πt – 2πy)
- d)y = 3cos(π + 2πt – 2πx)
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wave...
The equation for a sinusoidal wave is given by:
y(x, t) = A sin(kx - ωt)
where:
y(x, t) is the displacement of the wave at position x and time t,
A is the amplitude of the wave,
k is the wave number,
x is the position along the wave,
ω is the angular frequency,
t is the time.
Given that the amplitude A = 3cm, time period T = 1s, wavelength λ = 1cm, and at x = 0, t = 0 the particle is at its mean position, we can find the values of k and ω:
k = 2π / λ = 2π / 1 = 2π cm^(-1)
ω = 2π / T = 2π / 1 = 2π rad/s
Therefore, the equation for the sinusoidal wave is:
y(x, t) = 3 sin(2πx - 2πt)
At x = 0, t = 0:
y(0, 0) = 3 sin(0) = 0
So, at x = 0, t = 0, the particle is at its mean position.
y(x, t) = A sin(kx - ωt)
where:
y(x, t) is the displacement of the wave at position x and time t,
A is the amplitude of the wave,
k is the wave number,
x is the position along the wave,
ω is the angular frequency,
t is the time.
Given that the amplitude A = 3cm, time period T = 1s, wavelength λ = 1cm, and at x = 0, t = 0 the particle is at its mean position, we can find the values of k and ω:
k = 2π / λ = 2π / 1 = 2π cm^(-1)
ω = 2π / T = 2π / 1 = 2π rad/s
Therefore, the equation for the sinusoidal wave is:
y(x, t) = 3 sin(2πx - 2πt)
At x = 0, t = 0:
y(0, 0) = 3 sin(0) = 0
So, at x = 0, t = 0, the particle is at its mean position.
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A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wave...
The wave number k = 2π/1 = 2π.
The angular frequency w = 2π/1 = 2π.
The particle at x=0, t=0 is moving up from its mean position, & the wave travels towards the positive x-axis so the equation will be:
y = 3sin(2πt – 2πx).
The angular frequency w = 2π/1 = 2π.
The particle at x=0, t=0 is moving up from its mean position, & the wave travels towards the positive x-axis so the equation will be:
y = 3sin(2πt – 2πx).
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A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer?
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A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer?.
A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer?.
Solutions for A sinusoidal wave has an amplitude of 3cm. Time period is 1s. The wavelength is 1cm. And at x = 0, t=0 the particle is at its mean position & moving upwards. What is the equation of the wave if it is travelling along the positive x-axis?a)y = 3sin(2πx – 2πt)b)y = 3sin(2πt – 2πx)c)x = 3sin(2πt – 2πy)d)y = 3cos(π + 2πt – 2πx)Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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