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An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V?
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An aqueous solution contains 28% W/W KOH If density of solution is 1.2...
**1. Molarity:**
Molarity (M) is defined as the number of moles of solute per liter of solution. To calculate the molarity of the KOH solution, we need to determine the number of moles of KOH present in 1 liter of the solution.
Given:
- The solution contains 28% w/w KOH, which means that 28 grams of KOH is present in 100 grams of the solution.
- The density of the solution is 1.25 g/mL, which means that 1 liter (1000 mL) of the solution has a mass of 1.25 kg (1250 g).
To calculate the number of moles of KOH:
1. Calculate the mass of KOH present in 1 liter of the solution:
Mass of KOH = (28 g/100 g) * 1250 g = 350 g
2. Convert the mass of KOH to moles:
Moles of KOH = Mass of KOH / Molar mass of KOH
The molar mass of KOH: (39.1 g/mol + 16.0 g/mol + 1.0 g/mol) = 56.1 g/mol
Moles of KOH = 350 g / 56.1 g/mol = 6.23 mol
3. Calculate the molarity:
Molarity (M) = Moles of KOH / Volume of solution in liters
Molarity (M) = 6.23 mol / 1 L = 6.23 M
Therefore, the molarity of the KOH solution is 6.23 M.
**2. Mole fraction of KOH:**
The mole fraction (X) is the ratio of the number of moles of one component to the total number of moles in the solution.
To calculate the mole fraction of KOH, we need to determine the total number of moles in the solution.
Total moles in the solution = Moles of KOH
Mole fraction of KOH = Moles of KOH / Total moles in the solution
Mole fraction of KOH = 6.23 mol / 6.23 mol = 1
Therefore, the mole fraction of KOH is 1.
**3. %W/V:**
%W/V (percentage weight/volume) is a measure of the weight of solute present in a given volume of solution.
To calculate %W/V of KOH, we need to determine the weight of KOH present in a given volume of the solution.
Given:
- The solution contains 28% w/w KOH, which means that 28 grams of KOH is present in 100 grams of the solution.
- The density of the solution is 1.25 g/mL.
To calculate %W/V:
1. Calculate the weight of KOH present in 1 mL of the solution:
Weight of KOH = (28 g/100 g) * 1.25 g = 0.35 g
2. Convert the weight of KOH to %W/V:
%W/V = (Weight of KOH / Volume of solution in mL) * 100
%W/V = (0.35 g / 1 mL) * 100 = 35%
Therefore, the %W/V of KOH in the solution
Molarity (M) is defined as the number of moles of solute per liter of solution. To calculate the molarity of the KOH solution, we need to determine the number of moles of KOH present in 1 liter of the solution.
Given:
- The solution contains 28% w/w KOH, which means that 28 grams of KOH is present in 100 grams of the solution.
- The density of the solution is 1.25 g/mL, which means that 1 liter (1000 mL) of the solution has a mass of 1.25 kg (1250 g).
To calculate the number of moles of KOH:
1. Calculate the mass of KOH present in 1 liter of the solution:
Mass of KOH = (28 g/100 g) * 1250 g = 350 g
2. Convert the mass of KOH to moles:
Moles of KOH = Mass of KOH / Molar mass of KOH
The molar mass of KOH: (39.1 g/mol + 16.0 g/mol + 1.0 g/mol) = 56.1 g/mol
Moles of KOH = 350 g / 56.1 g/mol = 6.23 mol
3. Calculate the molarity:
Molarity (M) = Moles of KOH / Volume of solution in liters
Molarity (M) = 6.23 mol / 1 L = 6.23 M
Therefore, the molarity of the KOH solution is 6.23 M.
**2. Mole fraction of KOH:**
The mole fraction (X) is the ratio of the number of moles of one component to the total number of moles in the solution.
To calculate the mole fraction of KOH, we need to determine the total number of moles in the solution.
Total moles in the solution = Moles of KOH
Mole fraction of KOH = Moles of KOH / Total moles in the solution
Mole fraction of KOH = 6.23 mol / 6.23 mol = 1
Therefore, the mole fraction of KOH is 1.
**3. %W/V:**
%W/V (percentage weight/volume) is a measure of the weight of solute present in a given volume of solution.
To calculate %W/V of KOH, we need to determine the weight of KOH present in a given volume of the solution.
Given:
- The solution contains 28% w/w KOH, which means that 28 grams of KOH is present in 100 grams of the solution.
- The density of the solution is 1.25 g/mL.
To calculate %W/V:
1. Calculate the weight of KOH present in 1 mL of the solution:
Weight of KOH = (28 g/100 g) * 1.25 g = 0.35 g
2. Convert the weight of KOH to %W/V:
%W/V = (Weight of KOH / Volume of solution in mL) * 100
%W/V = (0.35 g / 1 mL) * 100 = 35%
Therefore, the %W/V of KOH in the solution
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An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V?
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An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V?.
An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An aqueous solution contains 28% W/W KOH If density of solution is 1.25gm/ml then calculate 1- molarity 2- mole fraction of KOH 3- %W/V?.
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