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Energy E of a hydrogen atom with principal quantum number n is given by E = – 13.6/n2 eV. The energy of photon ejected when the electronjumps from n = 3 state to n = 2 state of hydrogenis approximately [2004]a)1.9 eV.b)1.5 eV.c)0.85 eVd)3.4 eVCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Energy E of a hydrogen atom with principal quantum number n is given by E = – 13.6/n2 eV. The energy of photon ejected when the electronjumps from n = 3 state to n = 2 state of hydrogenis approximately [2004]a)1.9 eV.b)1.5 eV.c)0.85 eVd)3.4 eVCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Energy E of a hydrogen atom with principal quantum number n is given by E = – 13.6/n2 eV. The energy of photon ejected when the electronjumps from n = 3 state to n = 2 state of hydrogenis approximately [2004]a)1.9 eV.b)1.5 eV.c)0.85 eVd)3.4 eVCorrect answer is option 'A'. Can you explain this answer?.

Solutions for Energy E of a hydrogen atom with principal quantum number n is given by E = – 13.6/n2 eV. The energy of photon ejected when the electronjumps from n = 3 state to n = 2 state of hydrogenis approximately [2004]a)1.9 eV.b)1.5 eV.c)0.85 eVd)3.4 eVCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

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