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Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer?.

Solutions for Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET. Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.

Here you can find the meaning of Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Among the statements (I - IV), the correct ones are :(I) Be has a smaller atomic radius compared to Mg.(II) Be has higher ionization enthalpy than Al.(III) Charge/radius ratio of Be is greater than that of Al.IV) Both Be and Al form mainly covalent compounds.a)(I), (II) and (IV)b)(I), (III) and (IV)c)(II), (III) and (IV)d)(I), (II) and (III)Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice NEET tests.