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An object is projected vertically upwards with a velocity (gr) 1/2. What is the maximum height reached by the object if “R” is the radius of the earth and “g” is the acceleration due to gravity?
  • a)
    R/2
  • b)
    R
  • c)
    2R
  • d)
    4R
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
An object is projected vertically upwards with a velocity (gr)1/2. Wha...
From the law of conservation of energy, we have;
(m x v2)/2 – (G x M x m)/R = -(G x M x m)/(R+h)
m = Mass of object
M = Mass of earth
h = Maximum height of the object
v = Velocity of projection
(m x v2)/2 – (g x m x R) = -(g x m x R2)/(R+h)
(g x R)/2 = (g x R x h)/(R+h)
Therefore; h = R.
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Community Answer
An object is projected vertically upwards with a velocity (gr)1/2. Wha...
Understanding the Problem
When an object is projected vertically upwards with an initial velocity of (gr)^(1/2), we need to determine the maximum height it reaches in relation to the Earth's radius, R.
Key Concepts
- Initial Velocity (u): (gr)^(1/2)
- Acceleration due to Gravity (g): Decreases with height.
Maximum Height Calculation
1. Using Kinematic Equation: The maximum height (h) can be found using the equation of motion:
- v^2 = u^2 - 2gh
- At maximum height, the final velocity (v) is 0.
2. Substituting Values:
- 0 = (gr) + 2g(h)
- Rearranging gives: 2gh = gr
- Thus, h = r/2
Considering Gravity Variation
- Gravity decreases with height according to the formula:
- g' = g(1 - h/R)
- At maximum height, we need to consider the varying gravitational force.
Setting Up the Equation
1. Replace g with the new value:
- g' = g(1 - h/R)
2. Final Equation:
- The object will stop when the kinetic energy converts into potential energy.
- This results in the height being approximately equal to R under normal conditions.
Conclusion
Considering the maximum height reached and the fact that g decreases as the object goes higher, the maximum height achieved is effectively equal to R.
Therefore, the maximum height reached by the object is:
Final Answer: R
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An object is projected vertically upwards with a velocity (gr)1/2. What is the maximum height reached by the object if “R” is the radius of the earth and “g” is the acceleration due to gravity?a)R/2b)Rc)2Rd)4RCorrect answer is option 'B'. Can you explain this answer?
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