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A glass rod 20 cm long is clamped at the middle. It is set into the longitudinal vibration.
If the emitted sound frequency is 4000 Hz, the velocity of sound in glass will be
- a)2800 m/s
- b)3200 m/s
- c)1600 m/s
- d)2000 m/s
Correct answer is option 'C'. Can you explain this answer?
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A glass rod 20 cm long is clamped at the middle. It is set into the l...
Given information:
- A glass rod of length 20 cm is clamped at the middle.
- The rod is set into longitudinal vibration.
- The emitted sound frequency is 4000 Hz.
To find: The velocity of sound in glass.
Solution:
When the glass rod vibrates, it sets up longitudinal waves in it. The velocity of sound in a medium is given by the formula:
v = fλ
where v is the velocity of sound, f is the frequency of the sound, and λ is the wavelength of the sound.
Since the glass rod is clamped at the middle, it vibrates in its fundamental mode, which means that the wavelength of the sound produced is twice the length of the rod. Therefore,
λ = 2L = 2 × 0.2 m = 0.4 m
Substituting the values of f and λ in the above formula, we get:
v = fλ = 4000 Hz × 0.4 m = 1600 m/s
Therefore, the velocity of sound in glass is 1600 m/s.
Answer: Option (c) 1600 m/s.
- A glass rod of length 20 cm is clamped at the middle.
- The rod is set into longitudinal vibration.
- The emitted sound frequency is 4000 Hz.
To find: The velocity of sound in glass.
Solution:
When the glass rod vibrates, it sets up longitudinal waves in it. The velocity of sound in a medium is given by the formula:
v = fλ
where v is the velocity of sound, f is the frequency of the sound, and λ is the wavelength of the sound.
Since the glass rod is clamped at the middle, it vibrates in its fundamental mode, which means that the wavelength of the sound produced is twice the length of the rod. Therefore,
λ = 2L = 2 × 0.2 m = 0.4 m
Substituting the values of f and λ in the above formula, we get:
v = fλ = 4000 Hz × 0.4 m = 1600 m/s
Therefore, the velocity of sound in glass is 1600 m/s.
Answer: Option (c) 1600 m/s.
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Community Answer
A glass rod 20 cm long is clamped at the middle. It is set into the l...
The length of the rod (L),
= 0.2 = λ/2 ⇒ λ = 0.4 m
∴ the velocity of the sound in gas (v),
= v x λ = 4000 x 0.4 = 1600 m/s
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A glass rod 20 cm long is clamped at the middle. It is set into the longitudinal vibration.If the emitted sound frequency is 4000 Hz, the velocity of sound in glass will bea)2800 m/sb)3200 m/sc)1600 m/sd)2000 m/sCorrect answer is option 'C'. Can you explain this answer?
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