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The work function of a metallic substance is 5 eV. The threshold frequency is approximately
- a)1.6 × 107 Hz
- b)8.68 × 1015 Hz
- c)9.68 × 1017 Hz
- d)1.2 × 1015 Hz
Correct answer is option 'D'. Can you explain this answer?
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The work function of a metallic substance is 5 eV. The threshold freq...
Work function (W0) and the threshold frequency (V0) are related as below
W0 = hv0
∴ 
= 1.2 x 1015Hz
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The work function of a metallic substance is 5 eV. The threshold freq...
Work Function and Threshold Frequency:
The work function of a metallic substance is the minimum amount of energy required to remove an electron from the surface of the metal. This energy is typically measured in electron volts (eV). The threshold frequency is the minimum frequency of light required to eject electrons from the metal surface.
Given Information:
- Work function = 5 eV
- Energy of a photon = Planck's constant × frequency
- Energy of a photon = Work function
Calculating the threshold frequency:
To calculate the threshold frequency, we can use the formula: Energy of a photon = Planck's constant × frequency. Since the energy of a photon is equal to the work function, we can write:
5 eV = Planck's constant × frequency
Planck's constant is approximately 4.135 × 10^-15 eV·s. Substituting this value into the equation:
5 eV = 4.135 × 10^-15 eV·s × frequency
Solving for frequency:
frequency = 5 eV / (4.135 × 10^-15 eV·s) ≈ 1.2 × 10^15 Hz
Therefore, the threshold frequency is approximately 1.2 × 10^15 Hz, which corresponds to option 'D'.
The work function of a metallic substance is the minimum amount of energy required to remove an electron from the surface of the metal. This energy is typically measured in electron volts (eV). The threshold frequency is the minimum frequency of light required to eject electrons from the metal surface.
Given Information:
- Work function = 5 eV
- Energy of a photon = Planck's constant × frequency
- Energy of a photon = Work function
Calculating the threshold frequency:
To calculate the threshold frequency, we can use the formula: Energy of a photon = Planck's constant × frequency. Since the energy of a photon is equal to the work function, we can write:
5 eV = Planck's constant × frequency
Planck's constant is approximately 4.135 × 10^-15 eV·s. Substituting this value into the equation:
5 eV = 4.135 × 10^-15 eV·s × frequency
Solving for frequency:
frequency = 5 eV / (4.135 × 10^-15 eV·s) ≈ 1.2 × 10^15 Hz
Therefore, the threshold frequency is approximately 1.2 × 10^15 Hz, which corresponds to option 'D'.
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The work function of a metallic substance is 5 eV. The threshold frequency is approximatelya)1.6 × 107 Hzb)8.68 × 1015 Hzc)9.68 × 1017 Hzd)1.2 × 1015 HzCorrect answer is option 'D'. Can you explain this answer?
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