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One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, then final temperature of the gas is (Cv = 20 J/K)a)100 Kb)150 Kc)195 Kd)255 KCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared
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One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, then final temperature of the gas is (Cv = 20 J/K)a)100 Kb)150 Kc)195 Kd)255 KCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, then final temperature of the gas is (Cv = 20 J/K)a)100 Kb)150 Kc)195 Kd)255 KCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, then final temperature of the gas is (Cv = 20 J/K)a)100 Kb)150 Kc)195 Kd)255 KCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice One mole of an ideal gas is allowed to expand reversibly and adiabatically from a temperature of 27°C. If the work done during the process is 3 kJ, then final temperature of the gas is (Cv = 20 J/K)a)100 Kb)150 Kc)195 Kd)255 KCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.