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Consider the following statements and select the incorrect statement.
  • a)
    The presence of a large magnetic flux through a coil maintains a current in the coil if the circuit is continuous.
  • b)
    A coil of a metal wire kept stationary in a non–uniform magnetic field has an e.m.f induced in it.
  • c)
    A charged particle enters a region of uniform magnetic field at an angle of 85° to the magnetic lines of force, the path of the particle is a circle.
  • d)
    There is no change in the energy of a charged particle moving in a magnetic field although a magnetic force is acting on it.
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Consider the following statements and select the incorrect statement...
Explanation:

The incorrect statement is option D - "There is no change in the energy of a charged particle moving in a magnetic field although a magnetic force is acting on it."

Reasoning:

When a charged particle moves in a magnetic field, it experiences a magnetic force. This force acts perpendicular to the direction of motion of the particle and its velocity vector. The magnetic force does not do any work on the particle, as it is perpendicular to the displacement of the particle. Therefore, the magnetic force does not change the kinetic energy of the particle.

However, the magnetic force does affect the direction of motion of the particle. As a result, the particle moves in a circular path (if the magnetic field is uniform and the particle's initial velocity is perpendicular to the magnetic field). The motion of the particle is characterized by its centripetal acceleration, which is given by the formula a = (mv^2)/r, where m is the mass of the particle, v is its velocity, and r is the radius of the circular path.

Since the particle is accelerating, its velocity changes direction, and it is continuously changing direction. This implies that the particle is doing work against the magnetic field. The work done by the magnetic field on the particle is given by W = Fd, where F is the magnetic force and d is the distance traveled by the particle. Since the force and the displacement are perpendicular, the work done by the magnetic field is zero.

Therefore, while the energy of the particle remains constant, the direction of its motion changes continuously, and it does work against the magnetic field.
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Community Answer
Consider the following statements and select the incorrect statement...
When a charged particle enters perpendicularly in a magnetic field, it moves in a circular path with a constant speed. Hence its kinetic energy also remains constant.
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Consider the following statements and select the incorrect statement.a)The presence of a large magnetic flux through a coil maintains a current in the coil if the circuit is continuous.b)A coil of a metal wire kept stationary in a non–uniform magnetic field has an e.m.f induced in it.c)A charged particle enters a region of uniform magnetic field at an angle of 85° to the magnetic lines of force, the path of the particle is a circle.d)There is no change in the energy of a charged particle moving in a magnetic field although a magnetic force is acting on it.Correct answer is option 'D'. Can you explain this answer?
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