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In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.
When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :
- a)0.17°
- b)0.57°
- c)1.7°
- d)0.07°
Correct answer is option 'B'. Can you explain this answer?
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In a Young’s double slit experiment, light of 500 nm is used to produ...
To solve this problem, we can use the formula for the angular width of the fringes in a Young's double slit experiment:
θ = λ / d
where:
θ is the angular width of the fringes,
λ is the wavelength of light used, and
d is the distance between the slits.
We are given that the wavelength of light used is 500 nm and the distance between the slits is 0.05 mm.
Converting the given values to the appropriate units:
λ = 500 nm = 500 × 10^-9 m
d = 0.05 mm = 0.05 × 10^-3 m
Now, substituting these values into the formula, we get:
θ = (500 × 10^-9 m) / (0.05 × 10^-3 m)
= (500 × 10^-9) / (0.05 × 10^-3)
= (500 / 0.05) × 10^-9 / 10^-3
= 10 × 10^-9 / 10^-3
= 10 × 10^-9 × 10^3
= 10 × 10^-6
= 10^-5
Therefore, the angular width of the fringes is 10^-5 radians.
To convert this to degrees, we can use the fact that 1 radian is approximately equal to 57.3 degrees:
θ (in degrees) = 10^-5 radians × 57.3 degrees/radian
≈ 0.573 × 10^-5 degrees
Rounding to the nearest tenth, the angular width of the fringes is approximately 0.6 × 10^-5 degrees, which is closest to option B) 0.57°.
θ = λ / d
where:
θ is the angular width of the fringes,
λ is the wavelength of light used, and
d is the distance between the slits.
We are given that the wavelength of light used is 500 nm and the distance between the slits is 0.05 mm.
Converting the given values to the appropriate units:
λ = 500 nm = 500 × 10^-9 m
d = 0.05 mm = 0.05 × 10^-3 m
Now, substituting these values into the formula, we get:
θ = (500 × 10^-9 m) / (0.05 × 10^-3 m)
= (500 × 10^-9) / (0.05 × 10^-3)
= (500 / 0.05) × 10^-9 / 10^-3
= 10 × 10^-9 / 10^-3
= 10 × 10^-9 × 10^3
= 10 × 10^-6
= 10^-5
Therefore, the angular width of the fringes is 10^-5 radians.
To convert this to degrees, we can use the fact that 1 radian is approximately equal to 57.3 degrees:
θ (in degrees) = 10^-5 radians × 57.3 degrees/radian
≈ 0.573 × 10^-5 degrees
Rounding to the nearest tenth, the angular width of the fringes is approximately 0.6 × 10^-5 degrees, which is closest to option B) 0.57°.
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In a Young’s double slit experiment, light of 500 nm is used to produ...
Given : Wavelength of light, λ = 500 nm Distance between the slits, d= 0.05 mm Angular width of the fringe formed,
= 0.01 rad = 0.57°.
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In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :a)0.17°b)0.57°c)1.7°d)0.07°Correct answer is option 'B'. Can you explain this answer?
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In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :a)0.17°b)0.57°c)1.7°d)0.07°Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :a)0.17°b)0.57°c)1.7°d)0.07°Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :a)0.17°b)0.57°c)1.7°d)0.07°Correct answer is option 'B'. Can you explain this answer?.
In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :a)0.17°b)0.57°c)1.7°d)0.07°Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :a)0.17°b)0.57°c)1.7°d)0.07°Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern.When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :a)0.17°b)0.57°c)1.7°d)0.07°Correct answer is option 'B'. Can you explain this answer?.
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