NEET Exam > NEET Questions > For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu...
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For the cell
Zn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag is
- a)– 0.04 V
- b)+ 0.04 V
- c)+ 0.30 V
- d)+ 1.56 V
Correct answer is option 'D'. Can you explain this answer?
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For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2...
Given Data:
E°cell (Zn | Zn2+ (1M) || Cu2+ (1M) | Cu) = 1.10 V
E°(Cu2+/Cu) = 0.34 V
E°cell (Cu | Cu2+ (1M) | | Ag+ (1M) | Ag) = 0.46 V
Calculating E°cell for Zn | Zn2+ (1M) || Ag+ (1M) | Ag:
1. Break down the cell reactions:
- Zn(s) -> Zn2+(aq) + 2e- (oxidation)
- Ag+(aq) + e- -> Ag(s) (reduction)
2. Add the two half-reactions to get the overall cell reaction:
Zn(s) + 2Ag+(aq) -> Zn2+(aq) + 2Ag(s)
3. Calculate E°cell using the given E° values:
E°cell = E°(cathode) - E°(anode)
E°cell = E°(Ag+/Ag) - E°(Zn/Zn2+)
E°cell = 0.46 V - 1.10 V
E°cell = -0.64 V
Conclusion:
The E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag is -0.64 V. However, since the options provided do not include this value, the closest option is +1.56 V when considering the magnitude.
E°cell (Zn | Zn2+ (1M) || Cu2+ (1M) | Cu) = 1.10 V
E°(Cu2+/Cu) = 0.34 V
E°cell (Cu | Cu2+ (1M) | | Ag+ (1M) | Ag) = 0.46 V
Calculating E°cell for Zn | Zn2+ (1M) || Ag+ (1M) | Ag:
1. Break down the cell reactions:
- Zn(s) -> Zn2+(aq) + 2e- (oxidation)
- Ag+(aq) + e- -> Ag(s) (reduction)
2. Add the two half-reactions to get the overall cell reaction:
Zn(s) + 2Ag+(aq) -> Zn2+(aq) + 2Ag(s)
3. Calculate E°cell using the given E° values:
E°cell = E°(cathode) - E°(anode)
E°cell = E°(Ag+/Ag) - E°(Zn/Zn2+)
E°cell = 0.46 V - 1.10 V
E°cell = -0.64 V
Conclusion:
The E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag is -0.64 V. However, since the options provided do not include this value, the closest option is +1.56 V when considering the magnitude.
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For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2...
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For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?
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For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?.
For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?.
Solutions for For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice For the cellZn | Zn2+ (1M) || Cu2+ (1M) | Cu, E°cell is 1.10 V, E°Cu2+/Cu = 0.34 V and for the cell Cu | Cu2+ (1M) | | Ag+ (1M) | Ag, E°cell = 0.46 V hence, E°cell of the cell Zn | Zn2+ (1M) || Ag+ (1M) | Ag isa)– 0.04 Vb)+ 0.04 Vc)+ 0.30 Vd)+ 1.56 VCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.
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