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A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.
- a)23.4 S cm2 mole–1
- b)23.2 S cm2 mole–1
- c)46.45 S cm2 mole–1
- d)54.64 S cm2 mole–1
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivi...
Given:
- Concentration of NaOH solution (C) = 0.5 M
- Resistance of the solution (R) = 31.6 ohm
- Cell constant (K) = 0.367 cm^(-1)
To Find:
Approximate molar conductance of the NaOH solution.
Formula:
Molar Conductance (Λ) = (K * 1000) / R
Solution:
1. Convert the cell constant from cm^(-1) to m^(-1):
- Cell constant (K) = 0.367 cm^(-1) = 0.367 * 10^(-2) m^(-1) = 3.67 * 10^(-3) m^(-1)
2. Substitute the values into the formula to calculate the molar conductance:
- Molar Conductance (Λ) = (3.67 * 10^(-3) m^(-1) * 1000) / 31.6 ohm
- Λ ≈ 116.46 mS/cm
3. Convert the molar conductance from mS/cm to S/cm:
- 1 mS/cm = 1 * 10^(-3) S/cm
- Λ ≈ 116.46 * 10^(-3) S/cm
- Λ ≈ 0.11646 S/cm
4. Convert the molar conductance from S/cm to S cm^2 mole^(-1):
- Λ ≈ 0.11646 S/cm * 100 cm^2 mole^(-1)
- Λ ≈ 11.646 S cm^2 mole^(-1)
5. The approximate molar conductance of the NaOH solution is 11.646 S cm^2 mole^(-1).
Therefore, the correct answer is option B) 11.646 S cm^2 mole^(-1).
- Concentration of NaOH solution (C) = 0.5 M
- Resistance of the solution (R) = 31.6 ohm
- Cell constant (K) = 0.367 cm^(-1)
To Find:
Approximate molar conductance of the NaOH solution.
Formula:
Molar Conductance (Λ) = (K * 1000) / R
Solution:
1. Convert the cell constant from cm^(-1) to m^(-1):
- Cell constant (K) = 0.367 cm^(-1) = 0.367 * 10^(-2) m^(-1) = 3.67 * 10^(-3) m^(-1)
2. Substitute the values into the formula to calculate the molar conductance:
- Molar Conductance (Λ) = (3.67 * 10^(-3) m^(-1) * 1000) / 31.6 ohm
- Λ ≈ 116.46 mS/cm
3. Convert the molar conductance from mS/cm to S/cm:
- 1 mS/cm = 1 * 10^(-3) S/cm
- Λ ≈ 116.46 * 10^(-3) S/cm
- Λ ≈ 0.11646 S/cm
4. Convert the molar conductance from S/cm to S cm^2 mole^(-1):
- Λ ≈ 0.11646 S/cm * 100 cm^2 mole^(-1)
- Λ ≈ 11.646 S cm^2 mole^(-1)
5. The approximate molar conductance of the NaOH solution is 11.646 S cm^2 mole^(-1).
Therefore, the correct answer is option B) 11.646 S cm^2 mole^(-1).
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Community Answer
A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivi...
Here, R = 31.6 ohm
∴ C = 1/R = 1/31.6 ohm-1 = 0.0316 ohm-1
Specific conductance = conductance x cell constant
= 0.0316 ohm-1 x 0.367 cm-1
= 0.0116 ohm-1 cm-1
Now, molar concentration = 0.5 M (given)
= 0.5 x 10-3 mole cm-3
= 23.2 S cm2 mol-1
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A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer?
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A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer?.
A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer?.
Solutions for A 0.5 M NaOH solution offers a resistance of 31.6 ohm in a conductivity cell at room temperature. What shall be the approximate molar conductance of this NaOH solution if cell constant of the cell is 0.367 cm–1.a)23.4 S cm2 mole–1b)23.2 S cm2 mole–1c)46.45 S cm2 mole–1d)54.64 S cm2 mole–1Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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