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The time taken by light to pass through 4 mm thick glass slab of refractive index 1.5 will be (velocity of light in air = 3 × 108 m/s)
- a)8 × 10–11 s
- b)2 × 10–11 s
- c)3 × 10–11 s
- d)4 × 10–11 s
Correct answer is option 'B'. Can you explain this answer?
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To find the time taken by light to pass through a glass slab, we can use the formula:
t = d/v
where t is the time taken, d is the thickness of the slab, and v is the velocity of light in the medium.
Given:
Thickness of the glass slab, d = 4 mm
Refractive index of the glass slab, n = 1.5
Velocity of light in air, v = 3 × 10^8 m/s
First, we need to find the velocity of light in the glass slab using the refractive index:
v' = v/n
Substituting the values, we have:
v' = (3 × 10^8 m/s) / 1.5
v' = 2 × 10^8 m/s
Now, we can calculate the time taken:
t = d/v'
t = (4 mm) / (2 × 10^8 m/s)
t = (4 × 10^-3 m) / (2 × 10^8 m/s)
t = 2 × 10^-11 s
Hence, the time taken by light to pass through the 4 mm thick glass slab of refractive index 1.5 is 2 × 10^-11 s.
Therefore, the correct answer is option B: 2 × 10^-11 s.
t = d/v
where t is the time taken, d is the thickness of the slab, and v is the velocity of light in the medium.
Given:
Thickness of the glass slab, d = 4 mm
Refractive index of the glass slab, n = 1.5
Velocity of light in air, v = 3 × 10^8 m/s
First, we need to find the velocity of light in the glass slab using the refractive index:
v' = v/n
Substituting the values, we have:
v' = (3 × 10^8 m/s) / 1.5
v' = 2 × 10^8 m/s
Now, we can calculate the time taken:
t = d/v'
t = (4 mm) / (2 × 10^8 m/s)
t = (4 × 10^-3 m) / (2 × 10^8 m/s)
t = 2 × 10^-11 s
Hence, the time taken by light to pass through the 4 mm thick glass slab of refractive index 1.5 is 2 × 10^-11 s.
Therefore, the correct answer is option B: 2 × 10^-11 s.
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The time taken by light to pass through 4 mm thick glass slab of refractive index 1.5 will be (velocity of light in air = 3 × 108 m/s)a)8 × 10–11 sb)2 × 10–11 sc)3 × 10–11 sd)4 × 10–11 sCorrect answer is option 'B'. Can you explain this answer?
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