Class 10 Exam > Class 10 Questions > Consider two circuits:(i) A: in which N ident...
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Consider two circuits:
(i) A: in which N identical bulbs are connected in series across a battery of emf E.
(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.
PA : Power dissipating in each bulb in A.
PB : Power dissipating in each bulb in B.
PAT : Total power delivered by battery in circuit A.
PBT : Total power delivered by battery in circuit B.
Choose the correct option:
(i) A: in which N identical bulbs are connected in series across a battery of emf E.
(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.
PA : Power dissipating in each bulb in A.
PB : Power dissipating in each bulb in B.
PAT : Total power delivered by battery in circuit A.
PBT : Total power delivered by battery in circuit B.
Choose the correct option:
- a)PA = N.PBT
- b)PBT = N2.PA
- c)PBT = N.PAT
- d)PB = N2.PA
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
Consider two circuits:(i) A: in which N identical bulbs are connected ...
Explanation:
Circuit A:
- In circuit A, N identical bulbs are connected in series across a battery of emf E.
- When bulbs are connected in series, the total resistance of the circuit increases as compared to a single bulb.
- As a result, the current flowing through each bulb decreases.
- The power dissipated in each bulb can be calculated using the formula: P = I^2 * R, where P is power, I is current, and R is resistance.
- Since the current decreases in a series circuit, the power dissipated in each bulb in circuit A (PA) will be less than the power dissipated in a single bulb (P) when it is connected individually across the same battery.
- Therefore, PA < />
Circuit B:
- In circuit B, N bulbs identical to those in circuit A are connected in parallel across a similar battery of emf E.
- When bulbs are connected in parallel, the total resistance of the circuit decreases as compared to a single bulb.
- As a result, the current flowing through each bulb increases.
- The power dissipated in each bulb can be calculated using the formula: P = I^2 * R, where P is power, I is current, and R is resistance.
- Since the current increases in a parallel circuit, the power dissipated in each bulb in circuit B (PB) will be greater than the power dissipated in a single bulb (P) when it is connected individually across the same battery.
- Therefore, PB > P.
Total Power Delivered:
- The total power delivered by the battery in circuit A (PAT) can be calculated by multiplying the power dissipated in each bulb (PA) by the number of bulbs (N).
- Therefore, PAT = N * PA.
- The total power delivered by the battery in circuit B (PBT) can be calculated by multiplying the power dissipated in each bulb (PB) by the number of bulbs (N).
- Therefore, PBT = N * PB.
Conclusion:
- From the above analysis, we can conclude that the power dissipated in each bulb in circuit B (PB) is greater than the power dissipated in each bulb in circuit A (PA).
- Hence, option 'D' is the correct answer: PB = N^2 * PA.
Circuit A:
- In circuit A, N identical bulbs are connected in series across a battery of emf E.
- When bulbs are connected in series, the total resistance of the circuit increases as compared to a single bulb.
- As a result, the current flowing through each bulb decreases.
- The power dissipated in each bulb can be calculated using the formula: P = I^2 * R, where P is power, I is current, and R is resistance.
- Since the current decreases in a series circuit, the power dissipated in each bulb in circuit A (PA) will be less than the power dissipated in a single bulb (P) when it is connected individually across the same battery.
- Therefore, PA < />
Circuit B:
- In circuit B, N bulbs identical to those in circuit A are connected in parallel across a similar battery of emf E.
- When bulbs are connected in parallel, the total resistance of the circuit decreases as compared to a single bulb.
- As a result, the current flowing through each bulb increases.
- The power dissipated in each bulb can be calculated using the formula: P = I^2 * R, where P is power, I is current, and R is resistance.
- Since the current increases in a parallel circuit, the power dissipated in each bulb in circuit B (PB) will be greater than the power dissipated in a single bulb (P) when it is connected individually across the same battery.
- Therefore, PB > P.
Total Power Delivered:
- The total power delivered by the battery in circuit A (PAT) can be calculated by multiplying the power dissipated in each bulb (PA) by the number of bulbs (N).
- Therefore, PAT = N * PA.
- The total power delivered by the battery in circuit B (PBT) can be calculated by multiplying the power dissipated in each bulb (PB) by the number of bulbs (N).
- Therefore, PBT = N * PB.
Conclusion:
- From the above analysis, we can conclude that the power dissipated in each bulb in circuit B (PB) is greater than the power dissipated in each bulb in circuit A (PA).
- Hence, option 'D' is the correct answer: PB = N^2 * PA.
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Community Answer
Consider two circuits:(i) A: in which N identical bulbs are connected ...
∴ We get PE = N2PA
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Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer?
Question Description
Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer?.
Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? for Class 10 2024 is part of Class 10 preparation. The Question and answers have been prepared according to the Class 10 exam syllabus. Information about Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 10 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer?.
Solutions for Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 10.
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Here you can find the meaning of Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Consider two circuits:(i) A: in which N identical bulbs are connected in series across a battery of emf E.(ii) B: in which N bulbs identical to those in A are connected in parallel across similar battery of emf E.PA : Power dissipating in each bulb in A.PB : Power dissipating in each bulb in B.PAT : Total power delivered by battery in circuit A.PBT : Total power delivered by battery in circuit B.Choose the correct option:a)PA = N.PBTb)PBT = N2.PAc)PBT = N.PATd)PB = N2.PACorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice Class 10 tests.
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