? In 10 second, a charge of 25 C leaves a battery and 200 joule of ene...
potential difference of 1 V across two points is equal to workdone of 1 J performed on 1C.
Hence to transfer 25C, workdone is 200 J means, the potential difference = 200 X 25 = 5000 V.
charge = current X time , hence current = 25 C / 10 s = 2.5 A
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? In 10 second, a charge of 25 C leaves a battery and 200 joule of ene...
This is the potential difference and this is the current flows from the battery
? In 10 second, a charge of 25 C leaves a battery and 200 joule of ene...
Calculating Potential Difference and Current in a Circuit
Calculating Potential Difference:
The energy delivered to the circuit can be calculated using the formula:
\[ E = Q \times V \]
where E is the energy (200 J), Q is the charge (25 C), and V is the potential difference across the battery.
Plugging in the values, we get:
\[ 200 J = 25 C \times V \]
\[ V = \frac{200 J}{25 C} = 8 V \]
Therefore, the potential difference across the battery is 8 volts.
Calculating Current:
The current flowing from the battery can be calculated using the formula:
\[ I = \frac{Q}{t} \]
where I is the current, Q is the charge (25 C), and t is the time taken for the charge to leave the battery (10 s).
Plugging in the values, we get:
\[ I = \frac{25 C}{10 s} = 2.5 A \]
Therefore, the current flowing from the battery is 2.5 amperes.
Explanation:
When a charge of 25 C leaves the battery, it carries energy of 200 J to the outside circuit. This energy is a result of the potential difference across the battery, which is 8 V. The current flowing from the battery is 2.5 A, which is calculated based on the charge leaving the battery in 10 seconds. The potential difference and current are fundamental parameters in understanding the behavior of circuits and the flow of electricity.
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