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A particle is moving in a circle of radius r under the action of a force F = ⍺r2 which is directed towards centre of the circle. Total mechanical energy (kinetic energy + potential energy) of the particle is (take potential energy = 0 for r = 0) :
  • a)
  • b)
  • c)
  • d)
    ⍺r3
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A particle is moving in a circle of radius r under the action of a fo...
As we know, dU = F.dr
As,
m2v2 = m⍺r3
or,
Total energy = Potential energy + kinetic energy
Now, from eqn (i) and (ii)
Total energy = K.E. + P.E.
=
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A particle is moving in a circle of radius r under the action of a force F = ⍺r2 which is directed towards centre of the circle. Total mechanical energy (kinetic energy + potential energy) of the particle is (take potential energy = 0 for r = 0) :a)b)c)d)⍺r3Correct answer is option 'B'. Can you explain this answer?
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