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Calculate the number of sigma(σ) and pi(π) bonds present in benzene (C6H6).
  • a)
    6 σ and 3 π
  • b)
    3 σ and 6 π
  • c)
    3 σ and 12 π
  • d)
    12 σ and 3 π
Correct answer is option 'D'. Can you explain this answer?
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Calculate the number of sigma(σ) and pi(π) bonds present in b...
Sigma bonds are the strongest type of covalent bond, formed by head-on overlapping. In benzene, there are 6(C-C) σ bonds and 6(C-H) σ bonds. Pi bonds are formed by lateral overlapping of atomic orbitals. There are totally 3(C=C) π bonds.
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Calculate the number of sigma(σ) and pi(π) bonds present in b...
Calculation of Sigma (σ) and Pi (π) bonds in Benzene (C6H6)

Structural Formula of Benzene:
- Benzene has a hexagonal ring structure with alternating single and double bonds.

Sigma (σ) Bonds:
- In benzene, each carbon-carbon bond involves one sigma bond.
- Benzene has 6 carbon-carbon single bonds, so it has a total of 6 sigma bonds.

Pi (π) Bonds:
- In benzene, the double bonds involve one sigma bond and one pi bond.
- Benzene has 3 double bonds, which means it has a total of 3 sigma bonds and 3 pi bonds.
- Additionally, the delocalized pi electrons in the benzene ring contribute to 3 more pi bonds, making a total of 6 pi bonds.

Conclusion:
- Therefore, benzene (C6H6) has a total of 12 sigma bonds (6 single bonds) and 6 pi bonds (3 from double bonds and 3 from delocalized pi electrons). Hence, the correct answer is option 'D' - 12 sigma bonds and 3 pi bonds.
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Calculate the number of sigma(σ) and pi(π) bonds present in benzene (C6H6).a)6 σ and 3 πb)3 σ and 6 πc)3 σ and 12 πd)12 σ and 3 πCorrect answer is option 'D'. Can you explain this answer?
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