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What is the value of pressure inside the bubble of radius 1cm, if the bubble is in water at a depth (H) of 1m? Assume atmospheric pressure to be 1atm, surface tension = 0.075N/m & density of water = 1000kg/m3.
- a)110015 Pa
- b)109985 Pa
- c)26 atm
- d)4 atm
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
What is the value of pressure inside the bubble of radius 1cm, if the ...
The pressure in the bubble will be more than the pressure just outside it by an amount 2S/R.
The pressure just outside the bubble is P0 + ρgh.
Therefore, pressure inside bubble = P0 + ρgh + 2S/R
= 105 + (1000*10*1) + (2*0.075/0.01)
= 110015 Pa.
The pressure just outside the bubble is P0 + ρgh.
Therefore, pressure inside bubble = P0 + ρgh + 2S/R
= 105 + (1000*10*1) + (2*0.075/0.01)
= 110015 Pa.
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Community Answer
What is the value of pressure inside the bubble of radius 1cm, if the ...
To find the value of pressure inside the bubble, we can use the Laplace's law for pressure inside a spherical bubble:
P = 2T/R
Where P is the pressure inside the bubble, T is the surface tension, and R is the radius of the bubble.
Given:
Radius of the bubble, R = 1 cm = 0.01 m
Surface tension, T = 0.075 N/m
Using the Laplace's law, we have:
P = 2 * 0.075 / 0.01
P = 15 N/m^2
Therefore, the pressure inside the bubble is 15 N/m^2.
P = 2T/R
Where P is the pressure inside the bubble, T is the surface tension, and R is the radius of the bubble.
Given:
Radius of the bubble, R = 1 cm = 0.01 m
Surface tension, T = 0.075 N/m
Using the Laplace's law, we have:
P = 2 * 0.075 / 0.01
P = 15 N/m^2
Therefore, the pressure inside the bubble is 15 N/m^2.
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What is the value of pressure inside the bubble of radius 1cm, if the bubble is in water at a depth (H) of 1m? Assume atmospheric pressure to be 1atm, surface tension = 0.075N/m & density of water = 1000kg/m3.a)110015 Pab)109985 Pac)26 atmd)4 atmCorrect answer is option 'A'. Can you explain this answer?
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