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30g water at 30°C is mixed with 1g of steam at 100℃. Calculate the final temperature of the mixture. Sw = 1cal/ g°C, Lvap= 540cal/g.
- a)49.67°C
- b)38.33°C
- c)53.67°C
- d)41.33°C
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
30g water at 30°C is mixed with 1g of steam at 100. Calculate the ...
To calculate the final temperature, we need to know the specific heat capacity of water. The specific heat capacity of water is approximately 4.18 J/g°C.
Using the formula:
Q = mcΔT
Where:
Q = heat transferred
m = mass of the substance (30g)
c = specific heat capacity of the substance (4.18 J/g°C)
ΔT = change in temperature
Since we are looking for the final temperature, we can rearrange the formula as:
ΔT = Q / (mc)
The heat transferred (Q) can be calculated using the formula:
Q = m × c × ΔT
Let's assume the change in temperature (ΔT) is x°C.
Q = 30g × 4.18 J/g°C × x°C
The heat transferred (Q) is equal to the heat gained or lost by the water. In this case, the water is losing heat, so Q would be negative. Let's assume the negative value of Q is -Q.
-Q = 30g × 4.18 J/g°C × x°C
Simplifying the equation:
Q = -30g × 4.18 J/g°C × x°C
Since Q is the negative value of -Q:
Q = 30g × 4.18 J/g°C × x°C
Now we can substitute the value of Q in the previous equation:
30g × 4.18 J/g°C × x°C = 30g × 4.18 J/g°C × x°C
Canceling out the common terms:
x = x
This means that the change in temperature is equal to itself, so the final temperature would be 30°C.
Using the formula:
Q = mcΔT
Where:
Q = heat transferred
m = mass of the substance (30g)
c = specific heat capacity of the substance (4.18 J/g°C)
ΔT = change in temperature
Since we are looking for the final temperature, we can rearrange the formula as:
ΔT = Q / (mc)
The heat transferred (Q) can be calculated using the formula:
Q = m × c × ΔT
Let's assume the change in temperature (ΔT) is x°C.
Q = 30g × 4.18 J/g°C × x°C
The heat transferred (Q) is equal to the heat gained or lost by the water. In this case, the water is losing heat, so Q would be negative. Let's assume the negative value of Q is -Q.
-Q = 30g × 4.18 J/g°C × x°C
Simplifying the equation:
Q = -30g × 4.18 J/g°C × x°C
Since Q is the negative value of -Q:
Q = 30g × 4.18 J/g°C × x°C
Now we can substitute the value of Q in the previous equation:
30g × 4.18 J/g°C × x°C = 30g × 4.18 J/g°C × x°C
Canceling out the common terms:
x = x
This means that the change in temperature is equal to itself, so the final temperature would be 30°C.
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Community Answer
30g water at 30°C is mixed with 1g of steam at 100. Calculate the ...
30*1*(T-30) = 1*540 + 1*1*(100-T)
∴ 30T – 900 = 540 + 100 – T
⇒ 31T = 1540
⇒ T = 49.67°C
∴ 30T – 900 = 540 + 100 – T
⇒ 31T = 1540
⇒ T = 49.67°C
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30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer?
Question Description
30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer?.
30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about 30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer?.
Solutions for 30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
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30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for 30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of 30g water at 30°C is mixed with 1g of steam at 100. Calculate the final temperature of the mixture. Sw= 1cal/ g°C, Lvap= 540cal/g.a)49.67°Cb)38.33°Cc)53.67°Cd)41.33°CCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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