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When ferrous sulphate crystals are strongly heated, the gas/vapour not evolved are of
- a)SO2
- b)SO3
- c)O2
- d)H2O
Correct answer is option 'C'. Can you explain this answer?
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When ferrous sulphate crystals are strongly heated, the gas/vapour not...
Heating Ferrous Sulphate Crystals
Ferrous sulphate crystals have the chemical formula FeSO4·7H2O. When these crystals are strongly heated, they undergo a decomposition reaction, breaking down into different compounds.
Decomposition Reaction
The decomposition reaction of ferrous sulphate crystals is as follows:
FeSO4·7H2O(s) → Fe2O3(s) + SO3(g) + H2O(g)
According to this reaction, the ferrous sulphate crystals break down into solid iron(III) oxide (Fe2O3), gaseous sulphur trioxide (SO3), and water vapor (H2O).
Evolved Gas/Vapour
The question asks us to identify the gas/vapour that is not evolved during the heating process. From the above reaction, we can see that three different compounds are produced when ferrous sulphate crystals are strongly heated. These are:
- Iron(III) oxide (Fe2O3)
- Sulphur trioxide (SO3)
- Water vapor (H2O)
Out of these three compounds, only one is not a gas/vapour. That compound is iron(III) oxide (Fe2O3).
Therefore, the correct answer to the question is option 'C', which is O2. This is not one of the compounds produced during the heating of ferrous sulphate crystals, and hence it is not the gas/vapour that is not evolved.
Ferrous sulphate crystals have the chemical formula FeSO4·7H2O. When these crystals are strongly heated, they undergo a decomposition reaction, breaking down into different compounds.
Decomposition Reaction
The decomposition reaction of ferrous sulphate crystals is as follows:
FeSO4·7H2O(s) → Fe2O3(s) + SO3(g) + H2O(g)
According to this reaction, the ferrous sulphate crystals break down into solid iron(III) oxide (Fe2O3), gaseous sulphur trioxide (SO3), and water vapor (H2O).
Evolved Gas/Vapour
The question asks us to identify the gas/vapour that is not evolved during the heating process. From the above reaction, we can see that three different compounds are produced when ferrous sulphate crystals are strongly heated. These are:
- Iron(III) oxide (Fe2O3)
- Sulphur trioxide (SO3)
- Water vapor (H2O)
Out of these three compounds, only one is not a gas/vapour. That compound is iron(III) oxide (Fe2O3).
Therefore, the correct answer to the question is option 'C', which is O2. This is not one of the compounds produced during the heating of ferrous sulphate crystals, and hence it is not the gas/vapour that is not evolved.
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Community Answer
When ferrous sulphate crystals are strongly heated, the gas/vapour not...
Ferrous sulphate crystals initially lose water of crystallization. Then on strong heating evolve SO2 and SO3.
So, O2 is not involved.
So, O2 is not involved.
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When ferrous sulphate crystals are strongly heated, the gas/vapour not evolved are ofa)SO2b)SO3c)O2d)H2OCorrect answer is option 'C'. Can you explain this answer?
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