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An SCR has ambient temperature of 25°C and Junction temperature of 50°C and Average power dissipated of 25 watt. If the junction temperature is reduced to 35°C, the percentage reduction in thermal resistance _______ 
    Correct answer is '60'. Can you explain this answer?
    Most Upvoted Answer
    An SCR has ambient temperature of 25°C and Junction temperature of...
    Concept
    Here,
    Pav = Average rate of heat generated at a thyristor Junction
    QJC = thermal resistance between the junction temperature TJ and case temperature TC
    QCS = thermal resistance between the case temperature TC and sink temperature
    QSA = thermal resistance between the sink temperature TS and ambient temperature TA
     
    Where QJA = QJC + QCS + QSA
    Calculations:
    TA = 25°C
    IJ = 50°C
    Pav = 25 watt

     ∴ % change in thermal resistance
     
     
    Free Test
    Community Answer
    An SCR has ambient temperature of 25°C and Junction temperature of...
    Since you mentioned that an SCR has an ambient temperature of 25, it is important to note that an SCR (Silicon Controlled Rectifier) is a semiconductor device used for controlling electric power.

    The ambient temperature refers to the temperature of the surrounding environment in which the SCR is operating. In this case, the ambient temperature is 25 degrees Celsius.

    The ambient temperature can have an impact on the performance and reliability of the SCR. It is important to consider the ambient temperature when designing and operating the SCR to ensure it operates within its specified temperature range.

    If the ambient temperature exceeds the recommended operating temperature range of the SCR, it can lead to overheating and thermal stress on the device, potentially leading to failure. Therefore, proper cooling and heat sinking measures should be implemented if necessary to maintain the SCR within its specified temperature limits.
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    An SCR has ambient temperature of 25°C and Junction temperature of 50°C and Average power dissipated of 25 watt. If the junction temperature is reduced to 35°C, the percentage reduction in thermal resistance _______Correct answer is '60'. Can you explain this answer?
    Question Description
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