Electrical Engineering (EE) Exam  >  Electrical Engineering (EE) Questions  >  A three-phase three pulse converter, fed from... Start Learning for Free
A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 Ω, E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation is 
  • a)
    2.1o
  • b)
    1.7o
  • c)
    3.15o
  • d)
    3.5o
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A three-phase three pulse converter, fed from three-phase 400 V, 50Hz ...
Given data:
- Three-phase three pulse converter
- Input: Three-phase 400 V, 50Hz supply
- Load: R = 2 Ω, E = 200 V
- Load current: 20 A
- Source inductance: 2 mH

To find: The value of the overlap angle for inverter operation.

Explanation:
1. Converter Operation:
- The given three-phase three-pulse converter is a type of inverter circuit used for converting DC power into AC power.
- It consists of six thyristors connected in a three-phase bridge configuration.
- The converter operates by controlling the firing angle of the thyristors to regulate the output voltage and frequency.

2. Load Current:
- The load current is constant at 20 A, which means the converter needs to supply a constant current to the load.

3. Source Inductance:
- The source inductance of 2 mH is present to limit the rate of change of current and reduce harmonics.
- It helps in maintaining a more sinusoidal current waveform.

4. Overlap Angle:
- The overlap angle is the angle between the conduction period of one thyristor and the beginning of the conduction period of the next thyristor.
- It determines the amount of overlap between the conduction periods of the thyristors and affects the output waveform and distortion.

5. Calculation of Overlap Angle:
- To calculate the overlap angle, we need to consider the load current waveform and the firing angles of the thyristors.
- Since the load current is constant at 20 A, the waveform will be a square wave.
- The firing angles of the thyristors determine the conduction periods and the overlap angle.

6. Firing Angles:
- In a three-pulse converter, three thyristors conduct at a time, and the other three are non-conducting.
- Let the firing angles of the thyristors be α, β, and γ.
- The conduction periods of the thyristors can be represented as:
- Thyristor 1: 0 to α
- Thyristor 2: α to β
- Thyristor 3: β to γ
- Thyristor 4: γ to π
- Thyristor 5: π to π+α
- Thyristor 6: π+α to π+β

7. Calculation of Overlap Angle (Contd.):
- The overlap angle can be calculated by subtracting the ending firing angle of one thyristor from the starting firing angle of the next thyristor.
- In this case, we need to calculate the overlap angle between Thyristor 3 and Thyristor 4.
- The starting firing angle of Thyristor 3 is β, and the ending firing angle of Thyristor 4 is γ.
- Therefore, the overlap angle can be calculated as: γ - β.

8. Finding the Overlap Angle:
- To find the overlap angle, we need to consider the load voltage and the converter operation.
- The load voltage is given as E = 200 V.
- The converter operation is in inverter mode
Free Test
Community Answer
A three-phase three pulse converter, fed from three-phase 400 V, 50Hz ...
Concept:
Effect of source inductance: The presence of source inductance affects the rectifier output voltage
V0 = Vd0 cos α – ΔVd0  

μ is the overlap angle


Also, ΔVd0 = f Ls I0 (1 pulse)
= 4 f Ls I0 (2 pulse)
= 3 f Ls I0 (3 pulse)
= 6 f Ls I0 (6 pulse)
Calculation:
V0 = -E0 + I0 R
Vd0 cos α – 3 f Ls I0 = -200 + (20)(2)


On solving we get cos α = - 0.57
⇒ α = 124.76°
For three pulse converters:

On solving the above equation for overlap angle (μ) we get
cos (α + μ) = -0.6145
μ = 3.15° 
Explore Courses for Electrical Engineering (EE) exam

Similar Electrical Engineering (EE) Doubts

Top Courses for Electrical Engineering (EE)

A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer?
Question Description
A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE). Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A three-phase three pulse converter, fed from three-phase 400 V, 50Hz supply, has a load R = 2 , E = 200 V, and large inductance so that load current is constant at 20A. If the source has an inductance of 2 mH, then the value of overlap angle for inverter operation isa)2.1ob)1.7oc)3.15od)3.5oCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
Explore Courses for Electrical Engineering (EE) exam

Top Courses for Electrical Engineering (EE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev