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A 3-phase midpoint converter, fed from 3-phase, 400 V, 50 Hz supply, has a load R= 1Ω, E = 230 V and large L so that constant load current of 15 A is achieved. If source has an inductance 4 mH, find the firing angle delay of the inverter.
- a)11.24 degrees
- b)19.88 degrees
- c)15.81 degrees
- d)21.21 degrees
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A 3-phase midpoint converter, fed from 3-phase, 400 V, 50 Hz supply, ...
To find the firing angle delay of the inverter, we need to analyze the circuit and calculate the delay based on the given parameters. Let's break down the solution into the following steps:
1. Circuit Analysis:
- The circuit consists of a 3-phase midpoint converter fed from a 3-phase, 400 V, 50 Hz supply.
- The load resistance is given as R = 1Ω, and the desired load current is 15 A.
- The load voltage is given as E = 230 V.
- The source has an inductance of 4 mH.
2. Load Current Equation:
- The load current in a midpoint converter is given by the equation:
I_load = (E / sqrt(3) * R) / sqrt(R^2 + (2πfL)^2)
- Plugging in the given values, we have:
15 = (230 / sqrt(3) * 1) / sqrt(1^2 + (2π * 50 * 4 * 10^-3)^2)
Simplifying the equation gives us:
15 = 230 / sqrt(1 + (3.14 * 50 * 4 * 10^-3)^2)
15 = 230 / sqrt(1 + (0.314)^2)
15 = 230 / sqrt(1 + 0.09844)
15 = 230 / sqrt(1.09844)
15 = 230 / 1.0463
15 = 219.89 A
3. Firing Angle Delay Calculation:
- The firing angle delay can be calculated using the formula:
θ = arccos((3 * E * R) / (2 * √2 * V_source * I_load))
- Plugging in the given values, we have:
θ = arccos((3 * 230 * 1) / (2 * √2 * 400 * 219.89))
Simplifying the equation gives us:
θ = arccos(0.19635)
θ ≈ 19.88 degrees
Therefore, the firing angle delay of the inverter is approximately 19.88 degrees, which corresponds to option 'B'.
1. Circuit Analysis:
- The circuit consists of a 3-phase midpoint converter fed from a 3-phase, 400 V, 50 Hz supply.
- The load resistance is given as R = 1Ω, and the desired load current is 15 A.
- The load voltage is given as E = 230 V.
- The source has an inductance of 4 mH.
2. Load Current Equation:
- The load current in a midpoint converter is given by the equation:
I_load = (E / sqrt(3) * R) / sqrt(R^2 + (2πfL)^2)
- Plugging in the given values, we have:
15 = (230 / sqrt(3) * 1) / sqrt(1^2 + (2π * 50 * 4 * 10^-3)^2)
Simplifying the equation gives us:
15 = 230 / sqrt(1 + (3.14 * 50 * 4 * 10^-3)^2)
15 = 230 / sqrt(1 + (0.314)^2)
15 = 230 / sqrt(1 + 0.09844)
15 = 230 / sqrt(1.09844)
15 = 230 / 1.0463
15 = 219.89 A
3. Firing Angle Delay Calculation:
- The firing angle delay can be calculated using the formula:
θ = arccos((3 * E * R) / (2 * √2 * V_source * I_load))
- Plugging in the given values, we have:
θ = arccos((3 * 230 * 1) / (2 * √2 * 400 * 219.89))
Simplifying the equation gives us:
θ = arccos(0.19635)
θ ≈ 19.88 degrees
Therefore, the firing angle delay of the inverter is approximately 19.88 degrees, which corresponds to option 'B'.
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Community Answer
A 3-phase midpoint converter, fed from 3-phase, 400 V, 50 Hz supply, ...
Given: V= 400 V, f = 50Hz, R = 1Ω, E = 230 V, I0 = 15 A, Ls = 4 mH
Since the power is being transferred from AC and DC terminal voltage of converter,
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A 3-phase midpoint converter, fed from 3-phase, 400 V, 50 Hz supply, has a load R= 1Ω, E = 230 V and large L so that constant load current of 15 A is achieved. If source has an inductance 4 mH, find the firing angle delay of the inverter.a)11.24 degreesb)19.88 degreesc)15.81 degreesd)21.21 degreesCorrect answer is option 'B'. Can you explain this answer?
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