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Two bodies of masses 0.1kg and 0.4kg move towards each other with the velocities 1m/s and 0.1 m/s respectively after collision they stick together In 10 sec the combined mass travels?
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Two bodies of masses 0.1kg and 0.4kg move towards each other with the ...
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Two bodies of masses 0.1kg and 0.4kg move towards each other with the ...
Given:
- Mass of body 1 (m1) = 0.1 kg
- Mass of body 2 (m2) = 0.4 kg
- Initial velocity of body 1 (u1) = 1 m/s
- Initial velocity of body 2 (u2) = 0.1 m/s
- Time (t) = 10 s

Step 1: Find the final velocities of the bodies after collision:
Since the bodies stick together after the collision, they have the same final velocity (v) after the collision. According to the law of conservation of momentum:

m1*u1 + m2*u2 = (m1 + m2)*v

Substituting the given values:

(0.1 kg)(1 m/s) + (0.4 kg)(0.1 m/s) = (0.1 kg + 0.4 kg)v

0.1 kg + 0.04 kg = 0.5 kg*v

0.14 kg = 0.5 kg*v

v = 0.14 kg / 0.5 kg

v = 0.28 m/s

Therefore, the final velocity of the combined mass after the collision is 0.28 m/s.

Step 2: Find the distance traveled by the combined mass:
Since the combined mass travels for 10 seconds, we can use the equation:

Distance (d) = velocity (v) * time (t)

Substituting the values:

d = 0.28 m/s * 10 s

d = 2.8 m

Therefore, the combined mass travels a distance of 2.8 meters in 10 seconds.

Conclusion:
After the collision, the two bodies of masses 0.1 kg and 0.4 kg stick together and move with a final velocity of 0.28 m/s. In 10 seconds, the combined mass travels a distance of 2.8 meters.
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