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In an all NOR gate realization of a combinational circuit all EVEN and ODD level gates behave like
  • a)
    OR and AND
  • b)
    AND and OR
  • c)
    OR and NOT
  • d)
    NOR and AND
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In an all NOR gate realization of a combinational circuit all EVEN and...
Explanation:

Introduction:
In a combinational circuit, a NOR gate realization implies that the circuit is composed entirely of NOR gates. When we talk about even and odd levels of gates, we are referring to the depth of the gates in the circuit.

Even and Odd Levels:
- Even Level Gates: These gates are at an even depth in the circuit, starting from the input.
- Odd Level Gates: These gates are at an odd depth in the circuit, starting from the input.

Behavior of Even and Odd Level Gates:
- Even Level Gates: These gates behave like AND gates in a NOR gate realization. This is because when you take the complement of the outputs of the even level gates, they resemble the behavior of AND gates.
- Odd Level Gates: These gates behave like OR gates in a NOR gate realization. This is because the NOR gate is essentially an inverted OR gate.

Implication:
Therefore, in an all NOR gate realization of a combinational circuit, all EVEN and ODD level gates behave like:

Option B: AND and OR
This understanding is crucial in designing and analyzing combinational circuits using NOR gates. By recognizing the behavior of even and odd level gates, engineers can efficiently implement logical functions with NOR gates.
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Community Answer
In an all NOR gate realization of a combinational circuit all EVEN and...
In an all NOR gate realization of a combinational circuit,
  • All Even level gates behave like AND gate
  • All Odd level gates behave like OR gate
In an all NAND gate realization of a combinational circuit,
  • All Even level gates behave like OR gate
  • All Odd level gates behave like AND gate
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In an all NOR gate realization of a combinational circuit all EVEN and ODD level gates behave likea)OR and ANDb)AND and ORc)OR and NOTd)NOR and ANDCorrect answer is option 'B'. Can you explain this answer?
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