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The maximum current that can be measured by a galvanometer of resistance 40 Ω is 10 mA. It is converted into a voltmeter that can read upto 50 V. The resistance to be connected is series with the galvanometer (in ohm) is

  • a)
    2010

  • b)
    4050

  • c)
    5040

  • d)
    4960

Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The maximum current that can be measured by a galvanometer of resistan...
To convert galvanometer into voltmeter, the necessary value of resistance to be connected in series with the galvanometer is
= 5000 − 40 = 4960Ω
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Community Answer
The maximum current that can be measured by a galvanometer of resistan...
Given:
Resistance of galvanometer (G) = 40 Ω
Maximum current that can be measured by galvanometer = 10 mA = 0.01 A
Maximum voltage that can be read by voltmeter = 50 V

To convert the galvanometer into a voltmeter:
A voltmeter is used to measure voltage, which means it needs to be connected in parallel with the circuit element for which the voltage is to be measured. To convert the galvanometer into a voltmeter, a resistor is connected in series with the galvanometer.

Using the formula:
The resistance (R) to be connected in series with the galvanometer to convert it into a voltmeter is given by:
R = (Vmax / Imax) - G

Substituting the given values:
R = (50 V / 0.01 A) - 40 Ω
R = 5000 Ω - 40 Ω
R = 4960 Ω

Therefore, the resistance to be connected in series with the galvanometer is 4960 Ω, which is approximately equal to 4690 Ω. Hence, the correct answer is option D.
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The maximum current that can be measured by a galvanometer of resistance 40 Ω is 10 mA. It is converted into a voltmeter that can read upto 50 V. The resistance to be connected is series with the galvanometer (in ohm) isa)2010b)4050c)5040d)4960Correct answer is option 'D'. Can you explain this answer?
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