NEET Exam > NEET Questions > A bar magnet having a magnetic moment of 2×1...
Start Learning for Free
A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field is
- a)12 J
- b)6 J
- c)2 J
- d)0.6 J
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate ...
Here,M = 2 × 104JT−1
B = 6 × 10−4T,θ1 = 0°,θ2 = 60°
W = MB(cosθ1 − cosθ2) = MB(1 − cos60°)
= 6 J
Free Test
FREE
| Start Free Test |
Community Answer
A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate ...
To find the work done in taking the magnet from a direction parallel to the magnetic field to a direction 60° from the field, we can use the equation:
W = -ΔU
Where W is the work done and ΔU is the change in potential energy.
The potential energy of a magnetic dipole in a magnetic field is given by the equation:
U = -m • B
Where U is the potential energy, m is the magnetic moment, and B is the magnetic field.
Let's calculate the potential energy at each direction and then find the change in potential energy.
1. Potential energy when the magnet is parallel to the field:
At this position, the angle between the magnetic moment and the magnetic field is 0°.
U1 = -m • B • cos(0°)
U1 = -m • B
2. Potential energy when the magnet is at 60° from the field:
At this position, the angle between the magnetic moment and the magnetic field is 60°.
U2 = -m • B • cos(60°)
U2 = -m • B • 0.5
U2 = -0.5 • U1
Now, let's calculate the change in potential energy:
ΔU = U2 - U1
ΔU = -0.5 • U1 - (-U1)
ΔU = -0.5 • U1 + U1
ΔU = 0.5 • U1
Finally, we can calculate the work done:
W = -ΔU
W = -0.5 • U1
Given that the magnetic moment of the bar magnet is 2×10^4 J T^-1 and the magnetic field is 6×10^-4 T, we can substitute these values into the equation:
W = -0.5 • (2×10^4 J T^-1) • (6×10^-4 T)
W = -0.5 • (2×10^4) • (6×10^-4) J
W = -6 J
Since work is a scalar quantity, the negative sign indicates that work is done by an external agent to change the orientation of the magnet.
Therefore, the correct answer is option B: 6 J.
W = -ΔU
Where W is the work done and ΔU is the change in potential energy.
The potential energy of a magnetic dipole in a magnetic field is given by the equation:
U = -m • B
Where U is the potential energy, m is the magnetic moment, and B is the magnetic field.
Let's calculate the potential energy at each direction and then find the change in potential energy.
1. Potential energy when the magnet is parallel to the field:
At this position, the angle between the magnetic moment and the magnetic field is 0°.
U1 = -m • B • cos(0°)
U1 = -m • B
2. Potential energy when the magnet is at 60° from the field:
At this position, the angle between the magnetic moment and the magnetic field is 60°.
U2 = -m • B • cos(60°)
U2 = -m • B • 0.5
U2 = -0.5 • U1
Now, let's calculate the change in potential energy:
ΔU = U2 - U1
ΔU = -0.5 • U1 - (-U1)
ΔU = -0.5 • U1 + U1
ΔU = 0.5 • U1
Finally, we can calculate the work done:
W = -ΔU
W = -0.5 • U1
Given that the magnetic moment of the bar magnet is 2×10^4 J T^-1 and the magnetic field is 6×10^-4 T, we can substitute these values into the equation:
W = -0.5 • (2×10^4 J T^-1) • (6×10^-4 T)
W = -0.5 • (2×10^4) • (6×10^-4) J
W = -6 J
Since work is a scalar quantity, the negative sign indicates that work is done by an external agent to change the orientation of the magnet.
Therefore, the correct answer is option B: 6 J.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Top Courses for NEETView all
A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer?
Question Description
A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer?.
A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A bar magnet having a magnetic moment of 2×104JT−1 is free to rotate in a horizontal plane. A horizontal magnetic field B = 6×10−4T exists in the space. The work done in taking the magnet slowly from a direction parallel to the field to a direction 60° from the field isa)12 Jb)6 Jc)2 Jd)0.6 JCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup