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The geometry and magnetic behaviour of the complex [Ni(CO)4] are
- a)square planar geometry and diamagnetic
- b)tetrahedral geometry and diamagnetic
- c)square planar geometry and paramagnetic
- d)tetrahedral geometry and paramagnetic.
Correct answer is option 'B'. Can you explain this answer?
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The geometry and magnetic behaviour of the complex [Ni(CO)4] area)squ...
Geometry and Magnetic Behaviour of [Ni(CO)4]
Geometry:
The complex [Ni(CO)4] has 4 CO ligands attached to a central Ni atom. The geometry of this complex can be either square planar or tetrahedral.
Magnetic Behaviour:
The magnetic behaviour of a complex depends on the number of unpaired electrons present in the outermost d-orbitals of the central metal atom.
a) Square planar geometry and diamagnetic: If the geometry of the complex is square planar, then the hybridization of the Ni atom will be dsp2. The electronic configuration of Ni in this case will be d8. Since all the electrons are paired, the complex will be diamagnetic.
b) Tetrahedral geometry and diamagnetic: If the geometry of the complex is tetrahedral, then the hybridization of the Ni atom will be sp3. The electronic configuration of Ni in this case will be d10. Since all the electrons are paired, the complex will be diamagnetic.
c) Square planar geometry and paramagnetic: If the geometry of the complex is square planar, and there are unpaired electrons in the d-orbitals of the Ni atom, then the complex will be paramagnetic. This can happen if one or more of the CO ligands is replaced by a ligand that causes the splitting of the d-orbitals. This splitting is called crystal field splitting, and it causes the energy levels of the d-orbitals to split into two sets. The set of d-orbitals with higher energy is called the eg set, and the set with lower energy is called the t2g set. If there are unpaired electrons in the eg set, then the complex will be paramagnetic.
d) Tetrahedral geometry and paramagnetic: If the geometry of the complex is tetrahedral, and there are unpaired electrons in the d-orbitals of the Ni atom, then the complex will be paramagnetic. This can happen if one or more of the CO ligands is replaced by a ligand that causes the splitting of the d-orbitals. If there are unpaired electrons in the t2g set, then the complex will be paramagnetic.
Therefore, since the complex [Ni(CO)4] has a tetrahedral geometry and all the electrons are paired, it will be diamagnetic.
Geometry:
The complex [Ni(CO)4] has 4 CO ligands attached to a central Ni atom. The geometry of this complex can be either square planar or tetrahedral.
Magnetic Behaviour:
The magnetic behaviour of a complex depends on the number of unpaired electrons present in the outermost d-orbitals of the central metal atom.
a) Square planar geometry and diamagnetic: If the geometry of the complex is square planar, then the hybridization of the Ni atom will be dsp2. The electronic configuration of Ni in this case will be d8. Since all the electrons are paired, the complex will be diamagnetic.
b) Tetrahedral geometry and diamagnetic: If the geometry of the complex is tetrahedral, then the hybridization of the Ni atom will be sp3. The electronic configuration of Ni in this case will be d10. Since all the electrons are paired, the complex will be diamagnetic.
c) Square planar geometry and paramagnetic: If the geometry of the complex is square planar, and there are unpaired electrons in the d-orbitals of the Ni atom, then the complex will be paramagnetic. This can happen if one or more of the CO ligands is replaced by a ligand that causes the splitting of the d-orbitals. This splitting is called crystal field splitting, and it causes the energy levels of the d-orbitals to split into two sets. The set of d-orbitals with higher energy is called the eg set, and the set with lower energy is called the t2g set. If there are unpaired electrons in the eg set, then the complex will be paramagnetic.
d) Tetrahedral geometry and paramagnetic: If the geometry of the complex is tetrahedral, and there are unpaired electrons in the d-orbitals of the Ni atom, then the complex will be paramagnetic. This can happen if one or more of the CO ligands is replaced by a ligand that causes the splitting of the d-orbitals. If there are unpaired electrons in the t2g set, then the complex will be paramagnetic.
Therefore, since the complex [Ni(CO)4] has a tetrahedral geometry and all the electrons are paired, it will be diamagnetic.
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The geometry and magnetic behaviour of the complex [Ni(CO)4] area)squ...
Ni(28):[Ar]3d84s2
∵ CO is a strong field ligand, so, unpaired electrons get paired.
Thus, the complex is sp3 hybridised with tetrahedral geometry and diamagnetic in nature.
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The geometry and magnetic behaviour of the complex [Ni(CO)4] area)square planar geometry and diamagneticb)tetrahedral geometry and diamagneticc)square planar geometry and paramagneticd)tetrahedral geometry and paramagnetic.Correct answer is option 'B'. Can you explain this answer?
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