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A pendulum clock runs faster by 5 seconds per day at 20oC and goes slow by 10 seconds per day at 35oC. It shows the correct time at a temperature of:
- a)27.5oC
- b)25 oC
- c)30 oC
- d)33 oC
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A pendulum clock runs faster by 5 seconds per day at 20oC and goes sl...
Introduction:
In this question, we are given that a pendulum clock runs faster by 5 seconds per day at 20°C and goes slow by 10 seconds per day at 35°C. We need to determine the temperature at which the clock shows the correct time.
Understanding the problem:
To solve this problem, we need to find the temperature at which the clock neither runs fast nor goes slow. This means that the clock should neither gain time nor lose time.
Solving the problem:
To find the correct temperature, we can analyze the given information:
1. Pendulum clock gains 5 seconds per day at 20°C:
At 20°C, the clock gains 5 seconds per day. This means that the clock is running faster than the actual time. Therefore, the actual time is slower than the shown time.
2. Pendulum clock loses 10 seconds per day at 35°C:
At 35°C, the clock loses 10 seconds per day. This means that the clock is running slower than the actual time. Therefore, the actual time is faster than the shown time.
3. Finding the correct temperature:
To find the correct temperature, we need to find the point where the clock neither gains nor loses time. This can be done by finding the average of the two given temperatures.
The average of 20°C and 35°C is (20 + 35) / 2 = 55 / 2 = 27.5°C.
Therefore, the correct temperature at which the clock shows the correct time is 27.5°C.
Conclusion:
The correct temperature at which the pendulum clock shows the correct time is 27.5°C.
In this question, we are given that a pendulum clock runs faster by 5 seconds per day at 20°C and goes slow by 10 seconds per day at 35°C. We need to determine the temperature at which the clock shows the correct time.
Understanding the problem:
To solve this problem, we need to find the temperature at which the clock neither runs fast nor goes slow. This means that the clock should neither gain time nor lose time.
Solving the problem:
To find the correct temperature, we can analyze the given information:
1. Pendulum clock gains 5 seconds per day at 20°C:
At 20°C, the clock gains 5 seconds per day. This means that the clock is running faster than the actual time. Therefore, the actual time is slower than the shown time.
2. Pendulum clock loses 10 seconds per day at 35°C:
At 35°C, the clock loses 10 seconds per day. This means that the clock is running slower than the actual time. Therefore, the actual time is faster than the shown time.
3. Finding the correct temperature:
To find the correct temperature, we need to find the point where the clock neither gains nor loses time. This can be done by finding the average of the two given temperatures.
The average of 20°C and 35°C is (20 + 35) / 2 = 55 / 2 = 27.5°C.
Therefore, the correct temperature at which the clock shows the correct time is 27.5°C.
Conclusion:
The correct temperature at which the pendulum clock shows the correct time is 27.5°C.
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Community Answer
A pendulum clock runs faster by 5 seconds per day at 20oC and goes sl...
….(i)
….(ii)Solving (1) and (2): T = 250C
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A pendulum clock runs faster by 5 seconds per day at 20oC and goes slow by 10 seconds per day at 35oC. It shows the correct time at a temperature of:a)27.5oCb)25 oCc)30 oCd)33 oCCorrect answer is option 'B'. Can you explain this answer?
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