NEET Exam > NEET Questions > For the reaction X2O4(l) → 2XO2(g)ΔU = 2.1 k...
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For the reaction X2O4(l) → 2XO2(g)
ΔU = 2.1 kcal, ΔS = 20 cal K−1 at 300K
Hence, ΔG is
- a)2.7 kcal
- b)- 2.7 kcal
- c)9.3 kcal
- d)-9.3 kcal
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
For the reaction X2O4(l) → 2XO2(g)ΔU = 2.1 kcal, ΔS = 20 cal K−1 at 3...
ΔH =ΔU + ΔngRT
Given, ΔU = 2.1 kcal,Δng = 2
R = 2 × 10−3 kcal, T = 300K
∴ ΔH = 2.1 + 2 × 2 × 10−3 × 300 = 3.3 kcal
Again ΔG = ΔH − TΔS
Given, ΔS = 20 × 10−3kcalK−1
On putting the value of ΔH in the equation, we get
ΔG = 3.3 − 300 × 20 × 10−3
= 3.3 − 6 × 103 × 10−3 = −2.7kcal
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For the reaction X2O4(l) → 2XO2(g)ΔU = 2.1 kcal, ΔS = 20 cal K−1 at 300KHence, ΔG isa)2.7 kcalb)- 2.7 kcalc)9.3 kcald)-9.3 kcalCorrect answer is option 'B'. Can you explain this answer?
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