NEET Exam > NEET Questions > A moving block having mass m, collides with ...
Start Learning for Free
A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will be
- a)0.5
- b)0.25
- c)0.8
- d)0.4
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A moving block having mass m, collides with another stationary block ...
Given:
- Mass of the moving block = m
- Mass of the stationary block = 4m
- Initial velocity of the lighter block = v
- Coefficient of restitution = e
Concepts:
- Coefficient of restitution (e) is a measure of the elasticity of a collision between two objects. It is defined as the ratio of the relative velocity of separation to the relative velocity of approach after a collision.
- The formula for coefficient of restitution is given by: e = (v2 - v1) / (u1 - u2), where v1 and v2 are the final velocities of the two objects and u1 and u2 are their initial velocities.
Analysis:
- Let the final velocity of the lighter block be v1' and the final velocity of the heavier block be v2'.
- Since the lighter block comes to rest after the collision, v1' = 0.
- The initial velocity of the heavier block is 0 (as it is stationary).
- Using the formula for coefficient of restitution, we can write: e = (v2' - 0) / (v - 0) = v2' / v.
Solution:
- We need to find the value of coefficient of restitution (e).
- From the given information, we know that the lighter block comes to rest after the collision, i.e., v1' = 0.
- Since the initial velocity of the heavier block is 0, v2' is also 0.
- Therefore, e = v2' / v = 0 / v = 0.
Answer:
The value of coefficient of restitution (e) is 0.
Explanation:
- The coefficient of restitution measures the elasticity of a collision. A value of 0 means the collision is perfectly inelastic, i.e., the objects stick together after the collision and move with a common velocity.
- In this case, since the lighter block comes to rest after the collision, it indicates a perfectly inelastic collision.
- Therefore, the value of coefficient of restitution is 0, which is given in option B.
- Mass of the moving block = m
- Mass of the stationary block = 4m
- Initial velocity of the lighter block = v
- Coefficient of restitution = e
Concepts:
- Coefficient of restitution (e) is a measure of the elasticity of a collision between two objects. It is defined as the ratio of the relative velocity of separation to the relative velocity of approach after a collision.
- The formula for coefficient of restitution is given by: e = (v2 - v1) / (u1 - u2), where v1 and v2 are the final velocities of the two objects and u1 and u2 are their initial velocities.
Analysis:
- Let the final velocity of the lighter block be v1' and the final velocity of the heavier block be v2'.
- Since the lighter block comes to rest after the collision, v1' = 0.
- The initial velocity of the heavier block is 0 (as it is stationary).
- Using the formula for coefficient of restitution, we can write: e = (v2' - 0) / (v - 0) = v2' / v.
Solution:
- We need to find the value of coefficient of restitution (e).
- From the given information, we know that the lighter block comes to rest after the collision, i.e., v1' = 0.
- Since the initial velocity of the heavier block is 0, v2' is also 0.
- Therefore, e = v2' / v = 0 / v = 0.
Answer:
The value of coefficient of restitution (e) is 0.
Explanation:
- The coefficient of restitution measures the elasticity of a collision. A value of 0 means the collision is perfectly inelastic, i.e., the objects stick together after the collision and move with a common velocity.
- In this case, since the lighter block comes to rest after the collision, it indicates a perfectly inelastic collision.
- Therefore, the value of coefficient of restitution is 0, which is given in option B.
Free Test
FREE
| Start Free Test |
Community Answer
A moving block having mass m, collides with another stationary block ...
Coefficient of Restitution (e) -
Ratio of relative velocity after collision to relative velocity before collision.
Let velocity of 4m mass is v after collision
then mv = 4mv
v = v/4v
= 1/4
= 0.25
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer?
Question Description
A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer?.
A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer?.
Solutions for A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A moving block having mass m, collides with another stationary block having mass 4m. The lighter block comes to rest after collision. When the initial velocity of the lighter block is v, then the value of coefficient of restitution (e) will bea)0.5b)0.25c)0.8d)0.4Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup