A male human is heterozygous for autosomal genes A and B and is also ...
The male human is heterozygous for autosomal gene A and B and also hemizygous for haemophilic gene h, then his genotype will be AaBbXhY because haemophilia is a sex linked trait that is present on X -chromosome. So, the total number of gametes will be abXh, abY, ABXh, ABY, AbXh, AbY aB Xh, aBY. So the proportion of abXh sperm will be 1/8
A male human is heterozygous for autosomal genes A and B and is also ...
Calculation of Proportion of ABH Sperms
To determine the proportion of ABH sperms produced by the male individual, we need to consider the genetic makeup of the individual.
Heterozygous for Autosomal Genes A and B
The individual is heterozygous for autosomal genes A and B. This means that he has two different alleles for each gene. As a result, he can produce four different types of gametes: AB, Ab, aB, and ab.
Hemizygous for Haemophilic Gene h
The individual is hemizygous for the haemophilic gene h. This means that he only has one allele for this gene. As a result, he can produce two different types of gametes: h and H.
Calculation of Proportion of ABH Sperms
To determine the proportion of ABH sperms, we need to consider the combination of the autosomal genes (A and B) and the haemophilic gene (h). Since the individual is heterozygous for genes A and B, and hemizygous for gene h, the proportion of ABH sperms will be 1/2 (from the combination of A and B) multiplied by 1/2 (from the combination of h), which equals 1/4.
Therefore, the proportion of ABH sperms produced by the male individual will be 1/8 (1/4 x 1/2), which corresponds to option 'A'.
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