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A diseased man marries a normal woman. They get three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease is
  • a)
    sex linked dominant
  • b)
    sex linked recessive
  • c)
    sex limited character
  • d)
    autosomal dominant
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A diseased man marries a normal woman. They get three daughters and f...
In the inheritance pattern of sex chromosomes X-chromosome of father always passes to daughter and X -chromosome of mother passes to son. As the father is diseased and all the girls inherit it, it is obvious the disease is sex-linked. The mother is not a carrier (as evident from the fact that no son is diseased). Thus, the gene is dominant and expresses even in heterozygous condition.
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A diseased man marries a normal woman. They get three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease isa)sex linked dominantb)sex linked recessivec)sex limited characterd)autosomal dominantCorrect answer is option 'A'. Can you explain this answer?
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