Hunar wrote two sections of CAT paper; Verbal and QA in the same order. The probability of her passing both sections is 0.6. The probability of her passing the verbal section is 0.8. What is the probability of her passing the QA section given that she has passed the Verbal section?a)0.75b)0.65c)0.85d)0.95Correct answer is option 'A'. Can you explain this answer?

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Hunar wrote two sections of CAT paper; Verbal and QA in the same order. The probability of her passing both sections is 0.6. The probability of her passing the verbal section is 0.8. What is the probability of her passing the QA section given that she has passed the Verbal section?

a)
0.75
b)
0.65
c)
0.85
d)
0.95

Correct answer is option 'A'. Can you explain this answer?

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Hunar wrote two sections of CAT paper; Verbal and QA in the same order...

Let P(QA) = passing QA’s section
P(V) = passing Verbal section
So, P(QA/V) = P(QA∩V)/P(V) = 0.6/0.8 = 0.75
Hence, the correct answer is option A.

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Hunar wrote two sections of CAT paper; Verbal and QA in the same order...

Given information:
- Probability of passing both sections (Verbal and QA) = 0.6
- Probability of passing the Verbal section = 0.8

To find:
- Probability of passing the QA section given that she has passed the Verbal section

Formula:
- The conditional probability is given by the formula: P(A|B) = P(A∩B) / P(B)

Solution:
In this problem, we need to find the probability of passing the QA section given that she has passed the Verbal section. Let's denote:
- Event A: Passing the QA section
- Event B: Passing the Verbal section

Given information:
- P(A∩B) = 0.6 (probability of passing both sections)
- P(B) = 0.8 (probability of passing the Verbal section)

We can use the formula for conditional probability to find P(A|B):
P(A|B) = P(A∩B) / P(B)

Substituting the given values:
P(A|B) = 0.6 / 0.8

Simplifying the expression:
P(A|B) = 0.75

Therefore, the probability of passing the QA section given that she has passed the Verbal section is 0.75.

Answer:
The correct answer is option A) 0.75.

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