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Oil of viscosity 100 CP is to be formed as shown in the following figure the pipe used for pumping has internal diameter of 7 cm if the efficiency of pump is 80% find the power required in what for pumping the oil at 30 metre cube per hour density oil is 300 kg per metre cube?
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Oil of viscosity 100 CP is to be formed as shown in the following figu...
Problem:
Oil of viscosity 100 CP is to be pumped through a pipe with an internal diameter of 7 cm. The pump has an efficiency of 80%. Determine the power required in watts to pump the oil at a rate of 30 cubic meters per hour. The density of the oil is 300 kg per cubic meter.

Given:
Viscosity of oil = 100 CP
Internal diameter of pipe = 7 cm
Efficiency of pump = 80%
Rate of pumping = 30 cubic meters per hour
Density of oil = 300 kg per cubic meter

Solution:
Step 1: Convert units
To solve the problem, we need to convert the given units into a consistent system. Let's convert the units as follows:
- Viscosity: 100 CP = 0.1 Pascal-second (Pa·s)
- Pipe diameter: 7 cm = 0.07 meters (m)
- Pump efficiency: 80% = 0.8
- Rate of pumping: 30 cubic meters per hour = 30 m³/h
- Density of oil: 300 kg per cubic meter = 300 kg/m³

Step 2: Calculate the flow rate
The flow rate of the oil can be calculated using the formula:
Flow rate (Q) = Area × Velocity

The area of the pipe can be calculated using the formula:
Area (A) = π × (diameter/2)²

Substituting the values:
Area (A) = π × (0.07/2)² = 0.003847 m²

The velocity can be calculated using the formula:
Velocity (V) = Flow rate (Q) / Area (A)

Substituting the values:
Velocity (V) = 30 m³/h / 0.003847 m² = 7787.15 m/h

Step 3: Calculate the power required
The power required to pump the oil can be calculated using the formula:
Power (P) = Pressure × Flow rate

The pressure can be calculated using the formula:
Pressure (P) = (Viscosity × Velocity) / (diameter/2)

Substituting the values:
Pressure (P) = (0.1 Pa·s × 7787.15 m/h) / (0.07/2) = 198250 Pa

The power required can be calculated using the formula:
Power (P) = (Pressure × Flow rate) / (Pump efficiency)

Substituting the values:
Power (P) = (198250 Pa × 30 m³/h) / 0.8 = 7451250 W

Therefore, the power required to pump the oil at a rate of 30 cubic meters per hour is 7451250 watts.
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Oil of viscosity 100 CP is to be formed as shown in the following figure the pipe used for pumping has internal diameter of 7 cm if the efficiency of pump is 80% find the power required in what for pumping the oil at 30 metre cube per hour density oil is 300 kg per metre cube?
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Oil of viscosity 100 CP is to be formed as shown in the following figure the pipe used for pumping has internal diameter of 7 cm if the efficiency of pump is 80% find the power required in what for pumping the oil at 30 metre cube per hour density oil is 300 kg per metre cube? for SSC 2024 is part of SSC preparation. The Question and answers have been prepared according to the SSC exam syllabus. Information about Oil of viscosity 100 CP is to be formed as shown in the following figure the pipe used for pumping has internal diameter of 7 cm if the efficiency of pump is 80% find the power required in what for pumping the oil at 30 metre cube per hour density oil is 300 kg per metre cube? covers all topics & solutions for SSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Oil of viscosity 100 CP is to be formed as shown in the following figure the pipe used for pumping has internal diameter of 7 cm if the efficiency of pump is 80% find the power required in what for pumping the oil at 30 metre cube per hour density oil is 300 kg per metre cube?.
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