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Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)
- a)6.67 × 1015J
- b)6.67 × 1011J
- c)4.42 × 10−15J
- d)4.42 × 10−18J
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Calculate the energy in Joule corresponding to light of wave length 4...
Calculation of Energy in Joule for Light of Wavelength 45nm
First, we need to find the frequency of the light using the formula:
\[ \text{frequency} = \frac{c}{\lambda} \]
where:
- \( c = 3 \times 10^8 \, \text{ms}^{-1} \) (speed of light)
- \( \lambda = 45 \times 10^{-9} \, \text{m} \) (wavelength of light)
Calculate Frequency of Light
\[ \text{frequency} = \frac{3 \times 10^8}{45 \times 10^{-9}} = 6.67 \times 10^{15} \, \text{Hz} \]
Calculate Energy of Light using Planck's Equation
Now, we can use Planck's equation to calculate the energy of the light:
\[ \text{Energy} = h \times \text{frequency} \]
where:
- \( h = 6.63 \times 10^{-34} \, \text{J s} \) (Planck's constant)
- Frequency = \( 6.67 \times 10^{15} \, \text{Hz} \)
\[ \text{Energy} = 6.63 \times 10^{-34} \times 6.67 \times 10^{15} = 4.42 \times 10^{-18} \, \text{J} \]
Therefore, the energy in Joules corresponding to light of wavelength 45nm is 4.42 × 10^-18J, which corresponds to option 'D'.
First, we need to find the frequency of the light using the formula:
\[ \text{frequency} = \frac{c}{\lambda} \]
where:
- \( c = 3 \times 10^8 \, \text{ms}^{-1} \) (speed of light)
- \( \lambda = 45 \times 10^{-9} \, \text{m} \) (wavelength of light)
Calculate Frequency of Light
\[ \text{frequency} = \frac{3 \times 10^8}{45 \times 10^{-9}} = 6.67 \times 10^{15} \, \text{Hz} \]
Calculate Energy of Light using Planck's Equation
Now, we can use Planck's equation to calculate the energy of the light:
\[ \text{Energy} = h \times \text{frequency} \]
where:
- \( h = 6.63 \times 10^{-34} \, \text{J s} \) (Planck's constant)
- Frequency = \( 6.67 \times 10^{15} \, \text{Hz} \)
\[ \text{Energy} = 6.63 \times 10^{-34} \times 6.67 \times 10^{15} = 4.42 \times 10^{-18} \, \text{J} \]
Therefore, the energy in Joules corresponding to light of wavelength 45nm is 4.42 × 10^-18J, which corresponds to option 'D'.
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Community Answer
Calculate the energy in Joule corresponding to light of wave length 4...
E = hc/λ [Given λ = 45nm = 45 × 10−9m]
On putting the given values in the equation, we get
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Question Description
Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)a)6.67 × 1015Jb)6.67 × 1011Jc)4.42 × 10−15Jd)4.42 × 10−18JCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)a)6.67 × 1015Jb)6.67 × 1011Jc)4.42 × 10−15Jd)4.42 × 10−18JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)a)6.67 × 1015Jb)6.67 × 1011Jc)4.42 × 10−15Jd)4.42 × 10−18JCorrect answer is option 'D'. Can you explain this answer?.
Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)a)6.67 × 1015Jb)6.67 × 1011Jc)4.42 × 10−15Jd)4.42 × 10−18JCorrect answer is option 'D'. Can you explain this answer? for NEET 2025 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)a)6.67 × 1015Jb)6.67 × 1011Jc)4.42 × 10−15Jd)4.42 × 10−18JCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Calculate the energy in Joule corresponding to light of wave length 45nm (Planck's constant h = 6.63 × 10−34J s, speed of light, c = 3 × 108ms−1)a)6.67 × 1015Jb)6.67 × 1011Jc)4.42 × 10−15Jd)4.42 × 10−18JCorrect answer is option 'D'. Can you explain this answer?.
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