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A flask of mercury is sealed off at 20 °C and is completely filled with mercury. If the bulk modulus for mercury is 25000 MPa and the coefficient of volume expansion of mercury is 1.82 × 10−4 °C−1 and the expansion of glass is ignored, the pressure of mercury within the flask at 100 °C will be
  • a)
    100 MPa
  • b)
    720 MPa
  • c)
    365 MPa
  • d)
    230 MPa
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A flask of mercury is sealed off at 20 °C and is completely filled wi...
= 1.46 × 10−2
Now the bulk modulus, where P is the pressure.
P = (25000) x 1.46 x 10-2 MPa = 365 MPa
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Community Answer
A flask of mercury is sealed off at 20 °C and is completely filled wi...
To determine the pressure of mercury within the flask at 100 °C, we need to consider the bulk modulus and coefficient of volume expansion of mercury.

1. Bulk modulus of mercury:
The bulk modulus of a material measures its resistance to compression. It represents the ratio of the change in pressure to the fractional change in volume. The bulk modulus of mercury is given as 25000 MPa.

2. Coefficient of volume expansion of mercury:
The coefficient of volume expansion of a material measures the change in volume per unit volume per degree change in temperature. For mercury, the coefficient of volume expansion is given as 1.82 × 10^(-4) °C^(-1).

3. Calculation:
Since the expansion of glass is ignored, we can assume that the volume of the flask remains constant. Therefore, the change in volume of mercury is equal to the change in volume of the flask.

Let's assume the initial volume of mercury in the flask is V, and the final temperature is T2 = 100 °C. The initial temperature is T1 = 20 °C.

The change in temperature is ΔT = T2 - T1 = 100 °C - 20 °C = 80 °C.

Using the coefficient of volume expansion, we can calculate the change in volume of mercury:
ΔV = V * β * ΔT
= V * (1.82 × 10^(-4) °C^(-1)) * 80 °C

Since the volume of mercury is assumed to be constant, the change in volume is equal to zero:
ΔV = 0

Therefore, we can write the equation:
V * (1.82 × 10^(-4) °C^(-1)) * 80 °C = 0

Solving for V, we get:
V = 0

Since the volume of mercury remains constant, the pressure is also constant. Therefore, the pressure of mercury within the flask at 100 °C is equal to the pressure at 20 °C.

Hence, the correct answer is option C) 365 MPa.
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A flask of mercury is sealed off at 20 °C and is completely filled with mercury. If the bulk modulus for mercury is 25000 MPa and the coefficient of volume expansion of mercury is 1.82 × 10−4 °C−1 and the expansion of glass is ignored, the pressure of mercury within the flask at 100 °C will bea)100 MPab)720 MPac)365 MPad)230 MPaCorrect answer is option 'C'. Can you explain this answer?
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A flask of mercury is sealed off at 20 °C and is completely filled with mercury. If the bulk modulus for mercury is 25000 MPa and the coefficient of volume expansion of mercury is 1.82 × 10−4 °C−1 and the expansion of glass is ignored, the pressure of mercury within the flask at 100 °C will bea)100 MPab)720 MPac)365 MPad)230 MPaCorrect answer is option 'C'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A flask of mercury is sealed off at 20 °C and is completely filled with mercury. If the bulk modulus for mercury is 25000 MPa and the coefficient of volume expansion of mercury is 1.82 × 10−4 °C−1 and the expansion of glass is ignored, the pressure of mercury within the flask at 100 °C will bea)100 MPab)720 MPac)365 MPad)230 MPaCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A flask of mercury is sealed off at 20 °C and is completely filled with mercury. If the bulk modulus for mercury is 25000 MPa and the coefficient of volume expansion of mercury is 1.82 × 10−4 °C−1 and the expansion of glass is ignored, the pressure of mercury within the flask at 100 °C will bea)100 MPab)720 MPac)365 MPad)230 MPaCorrect answer is option 'C'. Can you explain this answer?.
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