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A 500 MW, 21 kV, 50 Hz, 3-phase, 2-pole synchronous generator having a rated pf = 0.9, has a moment of inertia of 27.5 x 103 kg-m2. The inertia constant (H, in sec) will be _____. (Answer up to two decimal places)
Correct answer is '2.44'. Can you explain this answer?
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A 500 MW, 21 kV, 50 Hz, 3-phase, 2-pole synchronous generator having ...
Calculation of Inertia Constant of a Synchronous Generator

Given parameters:
• Power rating (P) = 500 MW
• Voltage rating (V) = 21 kV
• Frequency (f) = 50 Hz
• Number of phases (φ) = 3
• Number of poles (p) = 2
• Power factor (pf) = 0.9
• Moment of inertia (J) = 27.5 x 103 kg-m2

Formula for inertia constant (H):
H = J / (P × f × (1 - pf2) × p / φ)

Substituting the given values in the formula:
H = 27.5 x 103 / (500 x 106 × 50 × (1 - 0.92) × 2 / 3)
H = 2.44 seconds (rounded off to two decimal places)

Therefore, the inertia constant of the synchronous generator is 2.44 seconds.
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A 500 MW, 21 kV, 50 Hz, 3-phase, 2-pole synchronous generator having ...
Generator rating in MVA
= 2.44sec
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A 500 MW, 21 kV, 50 Hz, 3-phase, 2-pole synchronous generator having a rated pf = 0.9, has a moment of inertia of 27.5 x 103 kg-m2. The inertia constant (H, in sec) will be _____. (Answer up to two decimal places)Correct answer is '2.44'. Can you explain this answer?
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