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Ethyl propanoate on reduction with LiAlH4 yields
- a)Methanol
- b)Ethanol and propanol
- c)Propane.
- d)Mixture of ethanol and methanol.
Correct answer is option 'B'. Can you explain this answer?
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Ethyl propanoate on reduction with LiAlH4 yieldsa)Methanolb)Ethanol a...
Reduction of Ethyl Propanoate with LiAlH4
LiAlH4 is a strong reducing agent that can reduce various carbonyl compounds to their corresponding alcohols. Ethyl propanoate is an ester that contains a carbonyl group, which can be reduced to an alcohol by LiAlH4. The reaction mechanism involves the following steps:
1. Formation of an intermediate complex between LiAlH4 and the carbonyl group of Ethyl propanoate.
2. Transfer of a hydride ion (H-) from LiAlH4 to the carbonyl carbon, resulting in the formation of an alkoxyaluminum intermediate.
3. Hydrolysis of the alkoxyaluminum intermediate by water to yield the corresponding alcohol.
Therefore, the reduction of Ethyl propanoate with LiAlH4 yields a mixture of Ethanol and Propanol.
Conclusion
In conclusion, the reduction of Ethyl propanoate with LiAlH4 involves the transfer of a hydride ion from LiAlH4 to the carbonyl carbon, resulting in the formation of an alkoxyaluminum intermediate, which is then hydrolyzed by water to yield the corresponding alcohol. In this case, the reduction of Ethyl propanoate yields a mixture of Ethanol and Propanol.
LiAlH4 is a strong reducing agent that can reduce various carbonyl compounds to their corresponding alcohols. Ethyl propanoate is an ester that contains a carbonyl group, which can be reduced to an alcohol by LiAlH4. The reaction mechanism involves the following steps:
1. Formation of an intermediate complex between LiAlH4 and the carbonyl group of Ethyl propanoate.
2. Transfer of a hydride ion (H-) from LiAlH4 to the carbonyl carbon, resulting in the formation of an alkoxyaluminum intermediate.
3. Hydrolysis of the alkoxyaluminum intermediate by water to yield the corresponding alcohol.
Therefore, the reduction of Ethyl propanoate with LiAlH4 yields a mixture of Ethanol and Propanol.
Conclusion
In conclusion, the reduction of Ethyl propanoate with LiAlH4 involves the transfer of a hydride ion from LiAlH4 to the carbonyl carbon, resulting in the formation of an alkoxyaluminum intermediate, which is then hydrolyzed by water to yield the corresponding alcohol. In this case, the reduction of Ethyl propanoate yields a mixture of Ethanol and Propanol.
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Community Answer
Ethyl propanoate on reduction with LiAlH4 yieldsa)Methanolb)Ethanol a...
Esters on reduction with lithium aluminium hydride gives two units of primary alcohol. Reduction of ethyl propanoate with Lithium aluminium hydride gives ethanol and propanol.
Reduction of ester takes place via hydride transfer mechanism.
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Ethyl propanoate on reduction with LiAlH4 yieldsa)Methanolb)Ethanol and propanolc)Propane.d)Mixture of ethanol and methanol.Correct answer is option 'B'. Can you explain this answer?
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Ethyl propanoate on reduction with LiAlH4 yieldsa)Methanolb)Ethanol and propanolc)Propane.d)Mixture of ethanol and methanol.Correct answer is option 'B'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about Ethyl propanoate on reduction with LiAlH4 yieldsa)Methanolb)Ethanol and propanolc)Propane.d)Mixture of ethanol and methanol.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ethyl propanoate on reduction with LiAlH4 yieldsa)Methanolb)Ethanol and propanolc)Propane.d)Mixture of ethanol and methanol.Correct answer is option 'B'. Can you explain this answer?.
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