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A gaseous mixture was prepared by taking equal mole of CO and N2. If the total pressure of the mixture was found 1 atmosphere, the partial pressure of the nitrogen (N2) in the mixture is
  • a)
    1 atm
  • b)
    0.5 atm
  • c)
    0.8 atm
  • d)
    0.9 atm
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A gaseous mixture was prepared by taking equal mole of CO and N2. If ...
Number of moles of CO = Number of moles of N2
So, their mole fractions will be 0.5 each.
The partial pressure of the nitrogen in the mixture is equal to the product of mole fraction of nitrogen and total pressure.
So, 0.5 × 1 = 0.5 atm
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A gaseous mixture was prepared by taking equal mole of CO and N2. If the total pressure of the mixture was found 1 atmosphere, the partial pressure of the nitrogen (N2) in the mixture isa)1 atmb)0.5 atmc)0.8 atmd)0.9 atmCorrect answer is option 'B'. Can you explain this answer?
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