NEET Exam > NEET Questions > SiCl4 on hydrolysis forms 'X' and HCl. Compo...
Start Learning for Free
SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively are
- a)H2SiCl6, SiO2
- b)H4SiO4, Si
- c)SiO2, Si
- d)H4SiO4, SiO2
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 10...
Hydrolysis of SiCl4 forms 'X' and HCl:
- SiCl4 + 2H2O → H4SiO4 (X) + 4HCl
Compound 'X' loses water at 1000oC and gives 'Y':
- H4SiO4 → SiO2 (Y) + 2H2O
Therefore, compounds 'X' and 'Y' respectively are:
- H4SiO4 (silicic acid) and SiO2 (silica)
Explanation:
- SiCl4 is silicon tetrachloride, which is a covalent compound.
- When it reacts with water, it undergoes hydrolysis and forms H4SiO4 (silicic acid) and HCl (hydrochloric acid).
- Silicic acid is a weak acid and exists as a polymer in aqueous solution.
- When H4SiO4 is heated to 1000oC, it loses water and forms SiO2 (silica), which is a solid with a high melting point.
- Therefore, the compounds 'X' and 'Y' respectively are H4SiO4 (silicic acid) and SiO2 (silica).
Importance:
- Silica is a widely used material in various industries, such as glass, ceramics, electronics, and construction.
- Silicic acid and its derivatives also have applications in the production of silicones, detergents, and catalysts.
- The hydrolysis of SiCl4 is an important reaction in the synthesis of silica-based materials.
- SiCl4 + 2H2O → H4SiO4 (X) + 4HCl
Compound 'X' loses water at 1000oC and gives 'Y':
- H4SiO4 → SiO2 (Y) + 2H2O
Therefore, compounds 'X' and 'Y' respectively are:
- H4SiO4 (silicic acid) and SiO2 (silica)
Explanation:
- SiCl4 is silicon tetrachloride, which is a covalent compound.
- When it reacts with water, it undergoes hydrolysis and forms H4SiO4 (silicic acid) and HCl (hydrochloric acid).
- Silicic acid is a weak acid and exists as a polymer in aqueous solution.
- When H4SiO4 is heated to 1000oC, it loses water and forms SiO2 (silica), which is a solid with a high melting point.
- Therefore, the compounds 'X' and 'Y' respectively are H4SiO4 (silicic acid) and SiO2 (silica).
Importance:
- Silica is a widely used material in various industries, such as glass, ceramics, electronics, and construction.
- Silicic acid and its derivatives also have applications in the production of silicones, detergents, and catalysts.
- The hydrolysis of SiCl4 is an important reaction in the synthesis of silica-based materials.
Free Test
FREE
| Start Free Test |
Community Answer
SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 10...
SiCl4 undergoes hydrolysis to form ortho silicic acid and hydrogen chloride, this hydrolysis reaction occurs due to the availability of vacant d orbitals in silicon atom.
Attention NEET Students!
To make sure you are not studying endlessly, EduRev has designed NEET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in NEET.
|
Explore Courses for NEET exam
|
|
Similar NEET Doubts
Top Courses for NEETView all
SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer?
Question Description
SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer?.
SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer?.
Solutions for SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for NEET.
Download more important topics, notes, lectures and mock test series for NEET Exam by signing up for free.
Here you can find the meaning of SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer?, a detailed solution for SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice SiCl4 on hydrolysis forms 'X' and HCl. Compound 'X' loses water at 1000oC and gives 'Y'. Compounds 'X' and 'Y' respectively area)H2SiCl6, SiO2b)H4SiO4, Sic)SiO2, Sid)H4SiO4, SiO2Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice NEET tests.
|
|
Explore Courses for NEET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup