Introduction:
The question asks for the change in diode voltage required to increase the current by a factor of 10 in an ideal pn junction diode operating in the forward bias region.

Explanation:

1. The current-voltage relationship in a pn junction diode:
- The current flowing through a pn junction diode is exponentially related to the voltage across it.
- In the forward bias region, the diode allows a significant amount of current to flow.
- The diode current is given by the equation:
I = I₀ * (e^(V/VT) - 1) ... (1)
where I is the diode current, I₀ is the reverse saturation current, V is the diode voltage, and VT is the thermal voltage.

2. Finding the change in diode voltage:
- We need to find the change in diode voltage that will cause the current to increase by a factor of 10.
- Let's assume the initial diode voltage is V₁ and the initial current is I₁.
- The new diode voltage required to increase the current by a factor of 10 is V₂.
- We can write the equation for the new current as:
10 * I₁ = I₀ * (e^(V₂/VT) - 1) ... (2)

3. Solving the equation:
- To solve equation (2) for V₂, we need to know the value of I₀ and VT.
- Since the diode is assumed to be ideal, the reverse saturation current I₀ is negligible.
- The thermal voltage VT is given by the equation:
VT = (k * T) / q
where k is the Boltzmann constant, T is the temperature in Kelvin, and q is the electronic charge.

4. Calculating the change in diode voltage:
- Let's assume a typical value for the thermal voltage VT, which is approximately 0.026 V at room temperature.
- Substituting the values in equation (2), we get:
10 * I₁ = 0.026 * (e^(V₂/0.026) - 1)
- Solving this equation for V₂ using numerical methods or a calculator, we find that V₂ is approximately 0.0596 V (rounded to one decimal place).

Conclusion:
The change in diode voltage required to increase the current by a factor of 10 in an ideal pn junction diode operating in the forward bias region is approximately 0.0596 V.