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A substance absorbs an amount of heat Q1 in going from one state to another and releases an amount of heat Q2 in coming back from the second state to the first state. How much work is done by the substance?
- a)Q1 / Q2
- b)Q1 - Q2
- c)Q2 / Q1
- d)Q1 + Q2
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A substance absorbs an amount of heat Q1 in going from one state to a...
Explanation:
When a substance absorbs heat Q1, it gains internal energy and undergoes a change in state. This change in state could be a phase change or a chemical reaction.
When the substance comes back to its initial state, it releases heat Q2. This heat release could be due to the reverse reaction or the reverse phase change.
During these processes, work is done by the substance. This work could be due to the expansion or compression of the substance.
The work done by the substance is given by the difference between the heat absorbed and the heat released.
Mathematically, work done = Q1 - Q2
Therefore, the correct answer is option B.
When a substance absorbs heat Q1, it gains internal energy and undergoes a change in state. This change in state could be a phase change or a chemical reaction.
When the substance comes back to its initial state, it releases heat Q2. This heat release could be due to the reverse reaction or the reverse phase change.
During these processes, work is done by the substance. This work could be due to the expansion or compression of the substance.
The work done by the substance is given by the difference between the heat absorbed and the heat released.
Mathematically, work done = Q1 - Q2
Therefore, the correct answer is option B.
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Community Answer
A substance absorbs an amount of heat Q1 in going from one state to a...
Applying the first law of thermodynamics,
ΔQ = ΔU + W
Q1 - W12 = U2 – U1 ... (1)
-Q2 – W21 = U1 - U2 (As Q2 is released, it will be taken as negative)
Or W21 + Q2 = U2 – U1 ... (2)
Putting (2) in (1), we get
Q1 – W12 = Q2 + W21
Or Q1 – Q2 = W12 + W21 = W
Or W = Q1 – Q2
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