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An inductor of inductance 2.0 mH is connected across a charged capacitor of capacitance 5.0 μF and the resulting L-C circuit is set oscillating at its natural frequency. Let Q denote the instantaneous charge on the capacitor and I the current in the circuit. It is found that the maximum value of Q is 200  μC. When Q = 100 μC, what is the value of
  • a)
    10000
  • b)
    1000
  • c)
    100000
  • d)
    100
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
An inductor of inductance 2.0 mH is connected across a charged capaci...
This is a problem of L - C oscillations.
Charge stored in the capacitor oscillates simple harmonically as
Here, Q0 = maximum value of Q = 200  μC = 2 × 10−4 C
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An inductor of inductance 2.0 mH is connected across a charged capacitor of capacitance 5.0 μF and the resulting L-C circuit is set oscillating at its natural frequency. Let Q denote the instantaneous charge on the capacitor and I the current in the circuit. It is found that the maximum value of Q is 200  μC. When Q = 100 μC, what is the value of a)10000b)1000c)100000d)100Correct answer is option 'A'. Can you explain this answer?
Question Description
An inductor of inductance 2.0 mH is connected across a charged capacitor of capacitance 5.0 μF and the resulting L-C circuit is set oscillating at its natural frequency. Let Q denote the instantaneous charge on the capacitor and I the current in the circuit. It is found that the maximum value of Q is 200  μC. When Q = 100 μC, what is the value of a)10000b)1000c)100000d)100Correct answer is option 'A'. Can you explain this answer? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about An inductor of inductance 2.0 mH is connected across a charged capacitor of capacitance 5.0 μF and the resulting L-C circuit is set oscillating at its natural frequency. Let Q denote the instantaneous charge on the capacitor and I the current in the circuit. It is found that the maximum value of Q is 200  μC. When Q = 100 μC, what is the value of a)10000b)1000c)100000d)100Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An inductor of inductance 2.0 mH is connected across a charged capacitor of capacitance 5.0 μF and the resulting L-C circuit is set oscillating at its natural frequency. Let Q denote the instantaneous charge on the capacitor and I the current in the circuit. It is found that the maximum value of Q is 200  μC. When Q = 100 μC, what is the value of a)10000b)1000c)100000d)100Correct answer is option 'A'. Can you explain this answer?.
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