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The total number of alkenes possible by dehydrobromination of 3–bromo–3–cyclopentylhexane using alcoholic KOH is –
    Correct answer is '5'. Can you explain this answer?
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    The total number of alkenes possible by dehydrobromination of 3–bromo...
    The substrate has three different types of C-H. Therefore, first, three structural isomers of alkenes are expected as
    The last two alkenes II and III are also capable of showing geometrical isomerism which are
    Hence, two geometrical isomers for each of them will be counted giving a total of five alkenes.
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    The total number of alkenes possible by dehydrobromination of 3–bromo–3–cyclopentylhexane using alcoholic KOH is –Correct answer is '5'. Can you explain this answer?
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    The total number of alkenes possible by dehydrobromination of 3–bromo–3–cyclopentylhexane using alcoholic KOH is –Correct answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The total number of alkenes possible by dehydrobromination of 3–bromo–3–cyclopentylhexane using alcoholic KOH is –Correct answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The total number of alkenes possible by dehydrobromination of 3–bromo–3–cyclopentylhexane using alcoholic KOH is –Correct answer is '5'. Can you explain this answer?.
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