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The reaction of CH3 – CH = CH2 with HOCl will yield
  • a)
    2-Chloro-1-propanol
  • b)
    3-Chloro-2-propanol
  • c)
    1-Chloro-2-propanol
  • d)
    1-Chloro-1-propanol
Correct answer is option 'C'. Can you explain this answer?
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The reaction of CH3 – CH = CH2 with HOCl will yield 1-Chloro-2-propanol. Let's break down the reaction and explain it in detail:

1. Reaction mechanism:
The reaction between an alkene and a halogen takes place via an electrophilic addition mechanism. In this case, the alkene CH3 – CH = CH2 will react with the halogen source HOCl (hypochlorous acid).

2. Formation of the electrophile:
HOCl can dissociate in water to form H+ and OCl- ions. The OCl- ion acts as an electrophile in the reaction.

3. Addition of the electrophile:
The OCl- ion will attack the alkene by forming a covalent bond with one of the carbon atoms in the double bond. This leads to the formation of a cyclic intermediate, in which the chlorine atom is bonded to one of the carbon atoms and the other carbon atom is bonded to the oxygen atom.

4. Ring opening:
The cyclic intermediate formed in the previous step undergoes ring opening with the help of water (H2O) to yield the final product. The chlorine atom is now bonded to one of the carbon atoms, and the other carbon atom is bonded to the hydroxyl group (-OH) from water.

5. Product formation:
The final product obtained is 1-Chloro-2-propanol. This is because the chlorine atom is bonded to the carbon atom that was originally part of the double bond, and the hydroxyl group is bonded to the other carbon atom in the alkene. The chlorine atom is attached to the first carbon atom of the propene, and the hydroxyl group is attached to the second carbon atom.

In summary, the reaction of CH3 – CH = CH2 with HOCl results in the formation of 1-Chloro-2-propanol. The chlorine atom is bonded to the carbon atom that was originally part of the double bond, and the hydroxyl group is bonded to the other carbon atom in the alkene.
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The reaction of CH3 – CH = CH2 with HOCl will yielda)2-Chloro-1-propanolb)3-Chloro-2-propanolc)1-Chloro-2-propanold)1-Chloro-1-propanolCorrect answer is option 'C'. Can you explain this answer?
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