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A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, work required to pull the hanging part on the table is (a) MgL (b) L Mg /3 (c) L Mg /9 (d) L Mg/18 The correct answer is D how?
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A uniform chain of length L and mass M is lying on a smooth table and ...
Given:
- Length of the chain (L)
- Mass of the chain (M)
- One third of the length of the chain is hanging vertically down over the edge of the table
- Acceleration due to gravity (g)

To find:
The work required to pull the hanging part of the chain onto the table

Solution:
Step 1: Identifying the forces involved
- The weight of the hanging part of the chain acts vertically downwards
- The tension in the chain acts vertically upwards to balance the weight of the hanging part

Step 2: Analyzing the forces on the hanging part of the chain
- The weight of the hanging part is given by W = mg, where m is the mass of the hanging part and g is the acceleration due to gravity
- The tension in the chain is equal to the weight of the hanging part, as it balances the weight

Step 3: Calculating the work
- Work is defined as the dot product of force and displacement. In this case, the force is tension and the displacement is the length of the hanging part of the chain that needs to be pulled onto the table
- The length of the hanging part is one-third of the total length of the chain, which is L/3
- Therefore, the work done to pull the hanging part onto the table is given by:
Work = Tension * Displacement
= mg * (L/3)

Step 4: Simplifying the expression
- Substituting the value of weight (mg) from step 2, we get:
Work = W * (L/3)
= (mg) * (L/3)
= (Mg) * (L/3)

Step 5: Final answer
- Simplifying the expression further, we get:
Work = (Mg) * (L/3)
= (MgL)/3
= L Mg /3

Hence, the correct answer is (b) L Mg /3.
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A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, work required to pull the hanging part on the table is (a) MgL (b) L Mg /3 (c) L Mg /9 (d) L Mg/18 The correct answer is D how?
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A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, work required to pull the hanging part on the table is (a) MgL (b) L Mg /3 (c) L Mg /9 (d) L Mg/18 The correct answer is D how? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, work required to pull the hanging part on the table is (a) MgL (b) L Mg /3 (c) L Mg /9 (d) L Mg/18 The correct answer is D how? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A uniform chain of length L and mass M is lying on a smooth table and one third of its length is hanging vertically down over the edge of the table. If g is acceleration due to gravity, work required to pull the hanging part on the table is (a) MgL (b) L Mg /3 (c) L Mg /9 (d) L Mg/18 The correct answer is D how?.
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